- #1
nomadreid
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In my reading I came across the equation
ds2 = −dt2 + 2t/r dtdr + (1 − (t/r)2)dr2 + (BKr)2(dθ2 + sin2 θdϕ2)
where s is spacetime, t is time, r is radius and the others are not important for my question.
What I do not get is the "1" in the (1 − (t/r)2)dr2, or
dr2− ((t/r)2)dr2 .
This seems to lead to a mismatch in units, with the rest of the members of the equation ending up in time (squared) units, but the dr2 being in distance (squared) units. What gives?
(The paper itself is at http://arxiv.org/abs/grqc/9909016 )
Thanks.
ds2 = −dt2 + 2t/r dtdr + (1 − (t/r)2)dr2 + (BKr)2(dθ2 + sin2 θdϕ2)
where s is spacetime, t is time, r is radius and the others are not important for my question.
What I do not get is the "1" in the (1 − (t/r)2)dr2, or
dr2− ((t/r)2)dr2 .
This seems to lead to a mismatch in units, with the rest of the members of the equation ending up in time (squared) units, but the dr2 being in distance (squared) units. What gives?
(The paper itself is at http://arxiv.org/abs/grqc/9909016 )
Thanks.
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