Exploring the Mystery of "Wear Out" in Non-Mechanical Systems

In summary: This can eventually destroy the material's ability to conduct electricity.It usually takes a few years for most electronic parts to be affected by electromigration.
  • #1
SkepticJ
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I understand why mechanical systems that are not capable of self repair wear out, but for years now I've been totally puzzled as to why things which do not have wearing parts wear out, such as - phosphores, rechargable batteries, capacitors, fluorecent lights, electrodes, vacuum tubes, electroluminescent plastics, LEDs and so on. I understand why incandescent bulbs burn out though - because the tungsten filament subliminates under the intense heat until a place on the filament gets thin enough that the filament snaps in two, breaking the electrical circuit and putting the light out.
So, why do they?
 
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  • #2
Different reasons. For instance, fluorescents can die bacause of a bad ballast or starter or even a broken filament. Electrolytic capacitors fail when electrical contact between the electrode and electrolyte is broken. This can happen if the electrode forms an oxide layer or if the electrolyte degrades (especially with high temperatures) or if anyone of a handfull of other unlikely events occurs.

In short, and being poetic, things eventually fail because everything in the world will react with everything else in the world, given enough time.
 
  • #3
Because there are no moving parts on a macroscopic scale does not mean there isn't a storm of activity on the atomic and subatomic scale. Even small amounts of electrical current will cause corrosion of parts.
 
  • #4
DaveC426913 said:
Because there are no moving parts on a macroscopic scale does not mean there isn't a storm of activity on the atomic and subatomic scale. Even small amounts of electrical current will cause corrosion of parts.

Ah, thanks. :)

That doesn't explain what kills phosphores though. Also not why the bulb part of http://en.wikipedia.org/wiki/Sulfur_lamp" goes out. There's nothing inside the inert glass container but sulfur and argon, what is reacting inside to ruin it after 60,000 hours?
 
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  • #5
SkepticJ said:
There's nothing inside the inert glass container but sulfur and argon, what is reacting inside to ruin it after 60,000 hours?
Ain't no such thing as a truly isolated system!

Specific outgassing rate of air through glass is at least 10^{-9} mbar/cm2-sec.
Surface area of bulb = 100cm2 say
60,000 hrs = about 200 million sec

If your bulb started out at absolute vacuum, it would end up with about 20mbar worth of air in it at the end of its rated life, assuming all joints and seals are perfect and have no leaks. That's a 2% contamination.
 
  • #6
btw if you buy a pc today, and use it non-stop everyday, how many years does it take normally for the chips, transistors (and all p-n junctions) to get "corroded" by the fluctuating microcurrent? because these streams of electrons eventually destroy the band structure of the material won't it?

(neglect the hard drive, because it is mechanical)
 
  • #7
One of the biggest problems with long-term use of semiconductor devices is electromigration. When you have relatively high currents passing through small areas, over time, the electrons act as a type of "wind," physically moving the metallic contacts of the devices and creating shorts and opens.
 

FAQ: Exploring the Mystery of "Wear Out" in Non-Mechanical Systems

1. What is "wear out" in non-mechanical systems?

"Wear out" in non-mechanical systems refers to the gradual degradation or failure of a non-mechanical system over time. This can occur due to various factors such as environmental conditions, usage patterns, and material properties.

2. Why is it important to explore the mystery of "wear out" in non-mechanical systems?

Understanding the causes and mechanisms of "wear out" in non-mechanical systems is crucial for designing and maintaining reliable and long-lasting systems. It can also lead to the development of new materials and technologies that can improve the durability and performance of these systems.

3. How do scientists study "wear out" in non-mechanical systems?

Scientists use a combination of experimental and computational methods to study "wear out" in non-mechanical systems. This includes conducting accelerated aging tests, analyzing material properties, and creating computer simulations to model the behavior of the system over time.

4. What are some common examples of non-mechanical systems that experience "wear out"?

Some common examples of non-mechanical systems that experience "wear out" include electronic devices such as smartphones and laptops, solar panels, batteries, and chemical reactors. These systems are subject to various forms of degradation and failure over time.

5. What are some potential solutions to mitigate "wear out" in non-mechanical systems?

Potential solutions to mitigate "wear out" in non-mechanical systems include the use of more durable materials, improved design and maintenance practices, and the development of self-healing or self-repairing technologies. Additionally, understanding the root causes of "wear out" can help in identifying and implementing preventative measures to prolong the lifespan of these systems.

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