- #1
Chewy0087
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[Solved] Power-Truck Problem
P = 0.5mv² / t
P = F * d
Hey sorry again :P trying to sort out some problems...
For part 1, I'm not sure, basically, I did the equation;
P = 0.5mv^2 / t
Re-arranging to Pt = 0.5mv^2
Now velocity as a function of time;
[tex]\sqrt{\frac{2Pt}{m}}[/tex] = v (or d(displacement)/dt)
So displacement = [tex]\int\sqrt{\frac{2Pt}{m}}[/tex]
= [tex]\frac{t^1.5\sqrt{2P}}{{root of M}}[/tex]
Doesn't seem right. And;
Acceleration = [tex]\frac{1}{2}[/tex][tex]\sqrt{\frac{2P}{mt}}[/tex]
Sorry I know it's long but any help = great :P from here I think I can tackle the rest of the question.. also excuse my numerous latex fails :P
Homework Statement
Homework Equations
P = 0.5mv² / t
P = F * d
The Attempt at a Solution
Hey sorry again :P trying to sort out some problems...
For part 1, I'm not sure, basically, I did the equation;
P = 0.5mv^2 / t
Re-arranging to Pt = 0.5mv^2
Now velocity as a function of time;
[tex]\sqrt{\frac{2Pt}{m}}[/tex] = v (or d(displacement)/dt)
So displacement = [tex]\int\sqrt{\frac{2Pt}{m}}[/tex]
= [tex]\frac{t^1.5\sqrt{2P}}{{root of M}}[/tex]
Doesn't seem right. And;
Acceleration = [tex]\frac{1}{2}[/tex][tex]\sqrt{\frac{2P}{mt}}[/tex]
Sorry I know it's long but any help = great :P from here I think I can tackle the rest of the question.. also excuse my numerous latex fails :P
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