- #1
fuligni
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hello friends,
I have a question on the simple undamped and undriven pendulum. I see that according to the website:
http://www.gmi.edu/~drussell/Demos/Pendulum/Pendula.html
the angle of rotation, Theta(t), can be expressed in terms of the starting angle using the small angle approximation sin(theta) = theta.
my question is, what is the ratio of successive thetas if we measure theta in increments of half periods ? the website shows:
theta(t) = theta(t=0)*cos(wt+phi)
i am interested in the ratio: theta(t=T)/theta(t=0) = cos(wt+phi)
if we substitute w = sqrt(g/L) and t=T = 2*pi*sqrt(L/g) into the right side of this ratio we get:
ratio = cos(2*pi + phi)
but cos(2*pi) = 1.0.
I don't see where i am going wrong since shouldn't the angle decrease over time until it is zero and the pendulum is stopped.
I am curious to see if the ratio of successive theta's is constant.
thankyou,
chris
I have a question on the simple undamped and undriven pendulum. I see that according to the website:
http://www.gmi.edu/~drussell/Demos/Pendulum/Pendula.html
the angle of rotation, Theta(t), can be expressed in terms of the starting angle using the small angle approximation sin(theta) = theta.
my question is, what is the ratio of successive thetas if we measure theta in increments of half periods ? the website shows:
theta(t) = theta(t=0)*cos(wt+phi)
i am interested in the ratio: theta(t=T)/theta(t=0) = cos(wt+phi)
if we substitute w = sqrt(g/L) and t=T = 2*pi*sqrt(L/g) into the right side of this ratio we get:
ratio = cos(2*pi + phi)
but cos(2*pi) = 1.0.
I don't see where i am going wrong since shouldn't the angle decrease over time until it is zero and the pendulum is stopped.
I am curious to see if the ratio of successive theta's is constant.
thankyou,
chris
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