Exponential and Logarithmic Functions

[qtheory]

y=Ce^ktA) First find k. [Hint:Use the given information of y=100 when t=2, and y=300 when t=4 to compute k.]

B) Finally, find the value for C. [Hint use ine of the two pieces of information given in the problem to solve for C. in other words, use either y=100 when t=2 or use y=300 when 4=4 to compute C]. [Hint: to find t use y=1].

 

[jonah1]

DISCLAIMER: Beer soaked rambling/opinion/observation/reckoning ahead. Read at your own risk. Not to be taken seriously. In no event shall the wandering math knight-errant Sir jonah in his inebriated state be liable to anyone for special, collateral, incidental, or consequential damages in connection with or arising out of the use of his beer (and tequila) powered views.

y=Ce^ktA) First find k. [Hint:Use the given information of y=100 when t=2, and y=300 when t=4 to compute k.]

B) Finally, find the value for C. [Hint use ine of the two pieces of information given in the problem to solve for C. in other words, use either y=100 when t=2 or use y=300 when 4=4 to compute C]. [Hint: to find t use y=1].

Is that a challenge problem? I'm heavily intoxicated at the moment so it's not obvious if it is or not.

 

[MarkFL]

y=Ce^ktA) First find k. [Hint:Use the given information of y=100 when t=2, and y=300 when t=4 to compute k.]

B) Finally, find the value for C. [Hint use ine of the two pieces of information given in the problem to solve for C. in other words, use either y=100 when t=2 or use y=300 when 4=4 to compute C]. [Hint: to find t use y=1].

We are given:

\(\displaystyle y=Ce^{kt}\)

First, divide through by $C\ne0$ to get:

\(\displaystyle \frac{y}{C}=e^{kt}\)

Next convert from exponential to logarithmic form...what do you get?