- #1
ThomsonKevin
- 5
- 0
Tried simplifying it of course, but didn't get far. Here's tbe problem:
''Express 3sin(3x)-4cos(3x) in the form Rcos(3x+\alpha),\alpha\ge0;R>0. Hence, find the smallest possible value of x for which 3sin(3x)-4cos(3x)=4.''
Bit confusing for me, especially the last part. How do you solve this, lads?
''Express 3sin(3x)-4cos(3x) in the form Rcos(3x+\alpha),\alpha\ge0;R>0. Hence, find the smallest possible value of x for which 3sin(3x)-4cos(3x)=4.''
Bit confusing for me, especially the last part. How do you solve this, lads?