Expression for the gravitational potential Vgrav

In summary, the conversation discusses how to derive an expression for the gravitational potential at a general position x on the x-axis in a system with two fixed particles of equal mass. The potential can be found by using equation A, which takes into account the distance between the two masses, and adding the potentials due to each individual mass. Equation B, which is for electrostatic potential, is not needed in this scenario.
  • #1
c_m
9
0

Homework Statement



In a system where other gravitational influences can be discounted, two particles of equall mass m, are fixed at positions x= 0 and x= x0 on the x-axis.

1) derive an expression for the gravitational potential Vgrav at a general position x on the x-axis.?



Homework Equations



The only equations i can seem to find are:

A) for a test mass m at a distance r from another mass M
Vgrav(r) = (1/m)Egrav = (1/m)(-GmM/r) = -GM/r

B) V(r) = Q/ 4pie e0 r
Where e0 is the permittivity of free space



The Attempt at a Solution



Well to derive an expression usually means i have to combine and rearrange two separate expressions, but i do not know where to begin, maybe i don't need either of these expressions? could somebody please help me to understand what is goin on here? and prehaps where to start looking?
 
Physics news on Phys.org
  • #2
Equation A you have there is the gravitational potential. Equation B is the electrostatic potential so you won't need that. So you have two masses along the x-axis and you want to know the potential along the axis dues to those two masses. How do you think you should proceed from here?
 
  • #3
Thankyou for relpying

I have actually sent my work now but i did not really do this one, so i would still like to go through it to see what i should have done.

So i do need equation A then? but not B. do i need to find another expression now then for the potential? I just didnt know where to begin.
 
  • #4
When there is more than one mass involved you can sum the potentials.
 
  • #5
you mean like, V = G m1 m2 / r? rather than V = Gm/r?
 
  • #6
No. Work out the potential using equation A due to one mass, then the other and then add them together to find the potential due to both.
 

FAQ: Expression for the gravitational potential Vgrav

What is the equation for gravitational potential?

The equation for gravitational potential is Vgrav = -GM/r, where G is the gravitational constant (6.67 x 10-11 Nm2/kg2), M is the mass of the object creating the gravitational field, and r is the distance between the object and the point where the potential is being calculated.

What is the unit of measurement for gravitational potential?

The unit of measurement for gravitational potential is joules per kilogram (J/kg) or meters squared per second squared (m2/s2).

How is gravitational potential related to gravitational force?

Gravitational potential and gravitational force are related by the equation F = -dVgrav/dr, where F is the force and r is the distance. This means that the force is equal to the negative derivative of the potential with respect to distance.

Is gravitational potential a vector or a scalar quantity?

Gravitational potential is a scalar quantity, meaning it only has magnitude and no direction. This is because it is a measure of the potential energy of an object at a certain point in space, and potential energy is a scalar quantity.

How does the gravitational potential change as distance from the source object increases?

The gravitational potential decreases as distance from the source object increases. This is because the force of gravity weakens with distance, and therefore the potential energy also decreases. This relationship follows an inverse square law, meaning that the potential energy is inversely proportional to the square of the distance.

Back
Top