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paulb42
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Homework Statement
A square loop with side-length a is positioned at the centre of a long thin solenoid, which has
radius r (with r > a), length l and N turns. The plane of the loop is perpendicular to the
5axis of the solenoid. A current I = I0 sin ωt flows through the loop. Derive an expression for
the time-averaged power dissipated in a resistance R connected between the terminals of the
solenoid. You may assume that R is much greater than the resistance of the solenoid and
that the self-inductance of the solenoid is negligible.
Homework Equations
P = J E d (this is meant to be the integral of the total volume of the shape in question)
P = I^2 * R
The Attempt at a Solution
I understand how the power dissipated is calculated over a macroscopic object. But how does this change when it is the referring to a solenoid and the terminals?