- #1
BlasterV
- 38
- 0
The German army in World War I shelled Paris with very large artillery pieces. These so-called 'Paris Guns' were actually a combination of two mortars stuck together. Pointed 55 degrees above the horizon, they fired shells with an initial speed of 1700 meters per second.
The guns were first used on March 23, 1918, a few days after the German army launched its last great offensive on the Western front. Three of the guns were located in Crepy-en-Laonnoise (about 8 km west-north-west of Laon), just behind the German lines.
Ok, I will show the parts I have solved so far first.
In the absence of air resistance, what was the range of the 'Paris' guns?
D = 277113.43613 m
How long was the shell in the air?
Time = 284.195607202 s
What is the distance from Crepy-en-Laonnoise to Paris?
D = 100 km (aka 100000 meters)
These 2 questions below are where it all falls apart:
If the Germans had wanted to shell London from the same spot in Crepy, what muzzle velocity would the shells have needed?
The distance from London to Crepy is 382797.19 m
Placing artillery on high ground extends its range. If the Germans wanted to shell London from Crepy with their existing 'Paris' guns, to what altitude would they have needed to lift the guns?
To be honest, all my attempts have been incorrect and I don't even think I'm close, so if someone can show me how these 2 parts are done it'd help alot.
I couldn't even comeup with a system to solve the first problem, so I have no work to show.
As for the second: (And none of this may even be remotely close) I tried it this way:
Vo x = 975.079941797
D Crepy to London/ Vo = T for mortar to make trip
T = 392.580314281 s
D = Vo y * t - 4.9 ( t^2 )
Answer is positive, since its height above ground.
D = 208493.541605 m
This answer is wrong.
Anyway, need help really bad, thanks!
Additional info: Vo y to paris = 1392.55847574 m/s
The guns were first used on March 23, 1918, a few days after the German army launched its last great offensive on the Western front. Three of the guns were located in Crepy-en-Laonnoise (about 8 km west-north-west of Laon), just behind the German lines.
Ok, I will show the parts I have solved so far first.
In the absence of air resistance, what was the range of the 'Paris' guns?
D = 277113.43613 m
How long was the shell in the air?
Time = 284.195607202 s
What is the distance from Crepy-en-Laonnoise to Paris?
D = 100 km (aka 100000 meters)
These 2 questions below are where it all falls apart:
If the Germans had wanted to shell London from the same spot in Crepy, what muzzle velocity would the shells have needed?
The distance from London to Crepy is 382797.19 m
Placing artillery on high ground extends its range. If the Germans wanted to shell London from Crepy with their existing 'Paris' guns, to what altitude would they have needed to lift the guns?
To be honest, all my attempts have been incorrect and I don't even think I'm close, so if someone can show me how these 2 parts are done it'd help alot.
I couldn't even comeup with a system to solve the first problem, so I have no work to show.
As for the second: (And none of this may even be remotely close) I tried it this way:
Vo x = 975.079941797
D Crepy to London/ Vo = T for mortar to make trip
T = 392.580314281 s
D = Vo y * t - 4.9 ( t^2 )
Answer is positive, since its height above ground.
D = 208493.541605 m
This answer is wrong.
Anyway, need help really bad, thanks!
Additional info: Vo y to paris = 1392.55847574 m/s