- #1
Pee-Buddy
- 4
- 0
F=ma prob with electrons (They don't even act like particles!)
Well here's the problem:
1. Electrons in an oscilloscope are accelerated from rest by a constant force of 8.0*10^16 N over a distance of 15mm. Find (a) the acceleration and (b) the final velocity.
Relevant equations:
2. F=ma, v^2+u^2=2as, v=ut+1/2at^2
At any rate it's easy to find the acceleration of 1 electron, but I don't know how to obtain the mass of all of them. I tried to find the force needed to displace a mass of 1 electron (9.1093897*10^-31 kg) by 15mm and then simply cross multiplying the forces and accelerations, but since I don't know the time (since I don't know the speed of the electron) I'm flumoxed!
3. The Attempt at a Solution :
F=ma => a= (8*10^16 N)/m(total)
a= (8*10^16 N)/(9.1093897*10^-31)x ;where is x =total no. of electrons
ax = 8.782147641^46 m/s^2
Again the final velocity is easy to get once I've gotten the acceleration. Any help would be appreciated.
Well here's the problem:
1. Electrons in an oscilloscope are accelerated from rest by a constant force of 8.0*10^16 N over a distance of 15mm. Find (a) the acceleration and (b) the final velocity.
Relevant equations:
2. F=ma, v^2+u^2=2as, v=ut+1/2at^2
At any rate it's easy to find the acceleration of 1 electron, but I don't know how to obtain the mass of all of them. I tried to find the force needed to displace a mass of 1 electron (9.1093897*10^-31 kg) by 15mm and then simply cross multiplying the forces and accelerations, but since I don't know the time (since I don't know the speed of the electron) I'm flumoxed!
3. The Attempt at a Solution :
F=ma => a= (8*10^16 N)/m(total)
a= (8*10^16 N)/(9.1093897*10^-31)x ;where is x =total no. of electrons
ax = 8.782147641^46 m/s^2
Again the final velocity is easy to get once I've gotten the acceleration. Any help would be appreciated.