- #1
trap101
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Solve the differential equation:
y(5)+12y(4)+104y(3)+408y''+564y'=0
where the (n) is the nth derivative.
So it's a 5th order DE. Now I'm trying to find the roots:
One of the roots is r = 0, which I obtain by factoring the equation into this form:
r(r4+12r3+104r2+408r+1156) = 0
No problem there. Now the other solutions are complex, my issue is how can I find those solutions from this 4th degree polynomial? I can't synthetically divide like it was just real numbers, so what do I do? The solution get's it into the form:
(r2+6r+34)2 from here I see how to get the complex, but how do I factor my above equation even to get this equation?
Besides that factoring issue I understand the problem.
Thanks
y(5)+12y(4)+104y(3)+408y''+564y'=0
where the (n) is the nth derivative.
So it's a 5th order DE. Now I'm trying to find the roots:
One of the roots is r = 0, which I obtain by factoring the equation into this form:
r(r4+12r3+104r2+408r+1156) = 0
No problem there. Now the other solutions are complex, my issue is how can I find those solutions from this 4th degree polynomial? I can't synthetically divide like it was just real numbers, so what do I do? The solution get's it into the form:
(r2+6r+34)2 from here I see how to get the complex, but how do I factor my above equation even to get this equation?
Besides that factoring issue I understand the problem.
Thanks