- #1
catcherintherye
- 48
- 0
x^16 + 1 is irreducible over the rationals, correct?...
...also I am required to factorise the following polynomials
2) i) x^5 + 3x^4 + 2x^3 + x^2 -7
ii) x^5 + 10x^4 + 13x^3 -25x^2 -68x -60
now I would usually approach this using the factor theorem to find a factor and then divide by this factor and continue, however in the question I am told as a hint that I am to try substituting x-> x+h h=+-1, +-2, why all this is necessary i canot think?...
...also I am required to factorise the following polynomials
2) i) x^5 + 3x^4 + 2x^3 + x^2 -7
ii) x^5 + 10x^4 + 13x^3 -25x^2 -68x -60
now I would usually approach this using the factor theorem to find a factor and then divide by this factor and continue, however in the question I am told as a hint that I am to try substituting x-> x+h h=+-1, +-2, why all this is necessary i canot think?...
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