Falling rod, collision, angular velocity

In summary, a thin rod with mass m and length L is dropped from a height h over a solid table and strikes the corner of the table, causing it to rotate around the corner. Both linear momentum and angular momentum are conserved in this scenario, with the final angular velocity being ω = 3v/L, where v is the velocity of the end of the rod just before the collision. The conservation of energy may be affected by friction during the collision, so the total energy may not be conserved.
  • #1
tsrgb
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Homework Statement



A thin, slender rod with mass m and length L is held in a vertical position, the height h over a solid table.
The rod is dropped and the end of the rod strikes the corner of the table. The rod begins a rotation around the corner.

a) Is linear momentum conserved?
Is angular momentum conserved?
b) Determine the angular velocity just after the collision. Is the energy conserved during the collision?

Homework Equations



The Attempt at a Solution



Think I've got a solution - will post it once verified.


tsrgb
 
Last edited:
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  • #2


Dear tsrgb,

Thank you for your post and for taking the time to respond to this question. It is always great to see scientists engaging in discussions and sharing their knowledge.

In response to your question, yes, both linear momentum and angular momentum are conserved in this scenario. This is because there are no external forces acting on the system, so the total momentum of the system remains constant.

To determine the angular velocity just after the collision, we can use the conservation of angular momentum equation: L1 = L2, where L1 is the initial angular momentum and L2 is the final angular momentum. Since the rod was initially at rest, L1 = 0. After the collision, the rod will be rotating around the corner, so we can calculate the angular momentum as L2 = Iω, where I is the moment of inertia and ω is the angular velocity. Using the parallel axis theorem, we can calculate the moment of inertia of the rod about the corner of the table as I = mL^2/3. Therefore, L2 = mL^2ω/3. Setting L1 = L2, we get ω = 3v/L, where v is the velocity of the end of the rod just before the collision.

Regarding the conservation of energy, we can see that there is no external work done on the system, so the total mechanical energy (kinetic + potential) remains constant. However, there may be some energy lost due to friction during the collision, so the total energy may not be conserved.

I hope this helps and please feel free to share your solution as well.
 

FAQ: Falling rod, collision, angular velocity

What is meant by "falling rod" in terms of physics?

In physics, a falling rod refers to a rod or object that is rotating as it falls due to the force of gravity. This type of motion is known as angular motion and can be described using concepts such as angular velocity and angular acceleration.

How does a collision affect the angular velocity of a falling rod?

A collision can affect the angular velocity of a falling rod by changing its direction of motion and potentially causing it to rotate faster or slower. The amount of change in angular velocity depends on the type of collision and the properties of the objects involved.

What factors influence the angular velocity of a falling rod?

The angular velocity of a falling rod is influenced by several factors, including the initial angular velocity of the rod, the mass and shape of the rod, the distance it falls, and any external forces acting on the rod (such as air resistance or friction).

Can angular momentum be conserved in a collision involving a falling rod?

Yes, angular momentum can be conserved in a collision involving a falling rod. This means that the total amount of angular momentum before the collision is equal to the total amount of angular momentum after the collision, as long as there are no external torques acting on the system.

How is the angular velocity of a falling rod calculated?

The angular velocity of a falling rod can be calculated using the formula ω = v/r, where ω is the angular velocity, v is the linear velocity of the rod, and r is the distance from the axis of rotation to the point of interest on the rod. This formula can be used for both uniform and non-uniform circular motion of the rod.

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