- #1
Azelketh
- 40
- 0
This is maddening and i cannot find a concise explanation anywhere despite the simplicity of this question.
I keep coming across faradays law expressed as
[tex] \text{curl}\left(\mathbf{E}\right) = -\frac{1}{C^2} \frac{\partial\mathbf{B}}{\partial t}
[/tex]
Im only used to working in SI units so all i can do is guess that this is expressed in gaussian units?
and
[tex] \text{curl}\left(\mathbf{E}\right) = -\frac{1}{C} \frac{\partial\mathbf{B}}{\partial t}
[/tex]
Can anyone explain these 2 different expressions of faradays law?
I keep coming across faradays law expressed as
[tex] \text{curl}\left(\mathbf{E}\right) = -\frac{1}{C^2} \frac{\partial\mathbf{B}}{\partial t}
[/tex]
Im only used to working in SI units so all i can do is guess that this is expressed in gaussian units?
and
[tex] \text{curl}\left(\mathbf{E}\right) = -\frac{1}{C} \frac{\partial\mathbf{B}}{\partial t}
[/tex]
Can anyone explain these 2 different expressions of faradays law?