Fermi energy contribute to the field in the inductor

In summary, the conversation discusses the use of a refrigerator with four walls made of copper and a silicon chip at the center. The chip is connected to an inductor and serves as an oscillating circuit. As the chip heats up, electrons pass into the inductor, contributing to the field. The question is what happens to the energy at this point and whether it can keep thermal energy out of the refrigerator. The conversation also mentions the Peltier-Seebeck effect and its use of dissimilar semiconductors, such as copper and bismuth. However, the speaker is interested in using silicon or germanium instead.
  • #1
silicool
5
0
Ok, so here's the basic idea. You have a refrigerator, with four walls each 6ft x 2ft x 4in. The walls are made out of copper(high thermal conductivity), with a silicon chip at the center. This chip is connected to an inductor and is essentially a L-C oscillating circuit. As the chip heats up, electrons pass into the conduction band as per Fermi-Dirac. These pass into the inductor. Once all the electrons with the Fermi energy contribute to the field in the inductor, it collapses and recharges the chip. My question is, what happens to the energy at this point and will this keep thermal energy out of the refrigerator.
 
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  • #3
I'm familiar with Peltier, but that isn't related to semiconductors. Peltier uses junctions of copper and bismuth, I'm thinking of something that uses silicon or germanium.
 
  • #4
Errm, Peltier effect works just fine between two dissimilar semiconductors.
 

FAQ: Fermi energy contribute to the field in the inductor

How does Fermi energy contribute to the field in an inductor?

The Fermi energy is a measure of the highest energy level occupied by electrons in a material at absolute zero temperature. In an inductor, the Fermi energy plays a role in determining the conductivity and resistivity of the material used for its construction. This, in turn, affects the strength and efficiency of the magnetic field produced by the inductor.

Why is Fermi energy important in inductor design?

Fermi energy is important in inductor design because it helps determine the type of material that should be used for the inductor. Materials with higher Fermi energy levels have lower resistivity, making them more suitable for high-frequency applications. This is because a lower resistivity allows for a more efficient flow of electrons, resulting in a stronger magnetic field.

How does the Fermi energy level affect the magnetic properties of an inductor?

The Fermi energy level directly affects the magnetic properties of an inductor through its influence on the material's conductivity. A higher Fermi energy level leads to a lower resistivity, allowing for a stronger and more stable magnetic field to be produced by the inductor.

Can the Fermi energy level be manipulated to improve inductor performance?

Yes, the Fermi energy level can be manipulated by altering the composition of the material used for the inductor. For example, doping techniques can be used to increase the Fermi energy level in a material, resulting in lower resistivity and improved inductor performance.

Are there any drawbacks to a high Fermi energy level in inductor design?

While a high Fermi energy level can improve inductor performance, it can also lead to higher losses due to increased eddy currents. This is especially true for high-frequency applications, where eddy currents can significantly impact the efficiency of the inductor. Therefore, it is important to carefully consider the balance between Fermi energy level and eddy current losses in inductor design.

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