Feynman's vs wiki's relativistic resultant

In summary: Both reference frames result in the same change to the test charge's momentum toward the wire even though the two reference frame's forces (F_1,F_2) are different (i.e. F_2=F_1*gamma) because the relative delta in time (t_1=t_2*gamma) is opposite the delta in forces so momentums p_1=p_2 (p_1=F_1*t_1, p_2=F_2*t_2=F_1*gamma*t_1/gamma=F_1*
  • #1
galvin452
15
0
In Feynman Lectures on Physics vol 2 pg.13.6-13.10 develops the equations for a current carrying wire and a moving charge ( negative test charge) with the same velocity as the electrons in the current. He looks at this situation from two reference frames, 1) the wire still and test charge and electrons moving at velocity v and 2) the test charge and conduction electrons still and the wire with velocity -v.

Using relativity and the Lorentz factor gamma for reference frame 2), the test charge sees an electric field, while from rest frame 1) the test charge sees a magnetic field. Both reference frames result in the same change to the test charge's momentum toward the wire even though the two reference frame's forces (F_1,F_2) are different (i.e. F_2=F_1*gamma) because the relative delta in time (t_1=t_2*gamma) is opposite the delta in forces so momentums p_1=p_2 (p_1=F_1*t_1, p_2=F_2*t_2=F_1*gamma*t_1/gamma=F_1*t_1=p_1).

In http://en.wikipedia.org/wiki/Relativistic_electromagnetism the section "The origin of magnetic forces" has almost the same situation except the current is carried by positive charges and the test charge is positive (rather than negative current and negative charge). However wiki has both a Lorentz contraction for the negative charge and a Lorentz expansion of the positive charge resulting in the same electrostatic force (F_e) as magnetic force (F_m), i.e. F_e=F_m. Or in terms of Feynman's notation, F_2=F_1.

These two do not agree, which one is correct and why? Or if both are why?
 
Physics news on Phys.org
  • #2
Moving lengths are shorter.

The observer at rest wrt the negative charges sees the "proper" spacing between negative charges and a contracted spacing between the positive ones.

The observer at rest wrt the positive charges see the proper spacing for the proper charges, and the spacing of the negative charges is contracted.

I suspect both are correct and you have misread both of them - has Feynman just left the Lorentz factor outside the F while wiki includes it? i.e. who measures each force?

In general - all observers should agree about the net force experienced by the test particle but will disagree about how that force comes about.
 
  • #3
Simon Bridge said:
In general - all observers should agree about the net force experienced by the test particle but will disagree about how that force comes about.

I gave you the summary but specifically Feynman equation (13.30) reads

F' = F/sqrt(1-v^2/c^2) (I wrote F_2=F_1*gamma)

where F' is reference frame 2 and F is reference frame 1 so this does not agree with your statement "all observers should agree about the net force experience".

So your saying that Feynman Lectures on Physics is wrong?
 
  • #4
The four-force, the rate of change of momentum with proper time, should be the same for all observers. The four-force is NOT the three force, though!

I'd suggest looking it up in a third source (other than wikki and Feynmann).
 
  • #5
In particular, the component of the 3-force that is parallel to the relative motion of the two inertial frames at a given instant of time has the same value in the moving frame as it does in the rest frame of the particle. The 3-force component perpendicular to the relative motion of the two inertial frames at that instant is always smaller by the value ##\frac{1}{\gamma}## in the moving frame as compared to its value in the particle's rest frame. See the entirety of chapter 5 of Purcell "Electricity and Magnetism" as well as appendix G of the same text.
 
  • #6
pervect said:
The four-force, the rate of change of momentum with proper time, should be the same for all observers. The four-force is NOT the three force, though!

WannabeNewton said:
In particular, the component of the 3-force that is parallel to the relative motion of the two inertial frames at a given instant of time has the same value in the moving frame as it does in the rest frame of the particle. The 3-force component perpendicular to the relative motion of the two inertial frames at that instant is always smaller by the value ##\frac{1}{\gamma}## in the moving frame as compared to its value in the particle's rest frame. See the entirety of chapter 5 of Purcell "Electricity and Magnetism" as well as appendix G of the same text.

I stand corrected - should have been more careful.
 
  • #7
galvin452 said:
In http://en.wikipedia.org/wiki/Relativistic_electromagnetism the section "The origin of magnetic forces" has almost the same situation except the current is carried by positive charges and the test charge is positive (rather than negative current and negative charge). However wiki has both a Lorentz contraction for the negative charge and a Lorentz expansion of the positive charge resulting in the same electrostatic force (F_e) as magnetic force (F_m), i.e. F_e=F_m.

Feynman also has a Lorentz contraction for one sign of charge and Lorentz expansion for the other sign of charge when going from the lab frame to the frame co-moving with q. (See Feynman’s 13.24 and 13.26). But, the wiki article makes an approximation for the gamma factors in the charge density (assuming v << c) , whereas Feynman does not make that approximation. You can see that wiki would get the same expressions for the forces as Feynman if wiki did not use the approximation. So, as I see it, there is no discrepancy.
 
  • #8
TSny said:
Feynman also has a Lorentz contraction for one sign of charge and Lorentz expansion for the other sign of charge when going from the lab frame to the frame co-moving with q. (See Feynman’s 13.24 and 13.26). But, the wiki article makes an approximation for the gamma factors in the charge density (assuming v << c) , whereas Feynman does not make that approximation. You can see that wiki would get the same expressions for the forces as Feynman if wiki did not use the approximation. So, as I see it, there is no discrepancy.

Thanks, for the feynman equation references. I also missed in the wiki equation for λ has in the middle has ≈ which is where the "(assuming v << c)" is.
 

FAQ: Feynman's vs wiki's relativistic resultant

What is Feynman's relativistic resultant?

Feynman's relativistic resultant is a mathematical formula developed by physicist Richard Feynman to calculate the effects of relativity on moving objects. It takes into account both time dilation and length contraction to determine the overall change in an object's position over a given period of time.

What is wiki's relativistic resultant?

Wiki's relativistic resultant is a simplified version of Feynman's formula that is commonly used on online sources such as Wikipedia. It still takes into account time dilation and length contraction, but it uses a different approach that is easier for non-scientists to understand.

How do Feynman's and wiki's relativistic resultants differ?

The main difference between Feynman's and wiki's relativistic resultants is in the level of complexity. While Feynman's formula is more accurate and takes into account more factors, it can be difficult to understand for those without a strong background in physics. Wiki's formula is a simplified version that is easier to use and understand, but it may not be as precise.

Which formula should I use for my calculations?

It depends on the level of accuracy and understanding that you need for your calculations. If you are a trained physicist or conducting research, Feynman's formula may be the better choice. However, if you are looking for a quick and simple solution, wiki's formula may be more suitable.

Can Feynman's or wiki's relativistic resultant be applied to all situations?

Feynman's and wiki's relativistic resultants are both based on the principles of special relativity, so they can be applied to most situations involving objects moving at high speeds. However, they may not be as accurate when dealing with extreme situations such as objects moving at near-light speeds or in the presence of strong gravitational fields.

Similar threads

Replies
34
Views
3K
Replies
27
Views
2K
Replies
20
Views
3K
Replies
28
Views
4K
Replies
7
Views
4K
Back
Top