- #1
glover_m
- 9
- 0
Prove Fn ≤ (7/4)n for all n, 0≤n
Fn = Fn-1 + Fn-2
Let P(n) be true for some n = k, for 0≤k
Let n = k+1
Fk+1 ≤ (7/4)k+1
LHS: Fk+1 = Fk + Fk-1 ≤ Fk-1 + (7/4)k ≤ (7/4)k-1 + (7/4)k
This last line is where I'm stuck, I feel like either I messed up early on, or I'm missing a way of simplifying this to look like (7/4)k+1
Fn = Fn-1 + Fn-2
Let P(n) be true for some n = k, for 0≤k
Let n = k+1
Fk+1 ≤ (7/4)k+1
LHS: Fk+1 = Fk + Fk-1 ≤ Fk-1 + (7/4)k ≤ (7/4)k-1 + (7/4)k
This last line is where I'm stuck, I feel like either I messed up early on, or I'm missing a way of simplifying this to look like (7/4)k+1