- #1
kiwi101
- 26
- 0
A 15cm focal-length converging lens is 18cm to the right of a 4.0cm focal-length converging lens. A 4.0cm tall object is distance to the left of the first lens.
For what value of is the final image of this two-lens system halfway between the two lenses?
My attempt:
I am working backwards:
s" = -9 (final virtual image displayed halfway between lenses)
f = 15
I solved for (1/s') + (1/s") = 1/f
s'= 5.6 cm (real image distance formed from lense 1)
f = 4cm
and now solve for s one more time and get s = 14
but that is wrong
For what value of is the final image of this two-lens system halfway between the two lenses?
My attempt:
I am working backwards:
s" = -9 (final virtual image displayed halfway between lenses)
f = 15
I solved for (1/s') + (1/s") = 1/f
s'= 5.6 cm (real image distance formed from lense 1)
f = 4cm
and now solve for s one more time and get s = 14
but that is wrong