Final temperature real gas behaving ideally

In summary, the conversation discusses a mixture of oxygen, nitrogen, and carbon dioxide being heated in a well-insulated vessel with 753 kJ of energy. It is assumed that the gases behave ideally according to Eq. 3.48, and the goal is to determine the final temperature of the mixture. The values of alpha, beta, and gamma for each gas are provided, as well as the gas constant R. The solution involves using a molar ratio to calculate the values for the mixture and then using the specific heat capacities to determine the change in temperature.
  • #1
Logan McEntire
4
0

Homework Statement


Please consider a mixture of oxygen (1 mole), nitrogen (4 mole), and carbon dioxide (3 mole). The mixture was heated in a well - insulated vessel with 753 kJ.

Determine the final temperature if the mixture is composed of real gases behaving ideally as described by Eq. 3.48 truncated after the third term.
Q=753000 J
O2: α=3.626 β=-1.878 γ=7.055
N2: α=3.675 β=-1.208 γ=2.324
CO2: α=2.401 β=8.735 γ=-6.607
R=8.314 kJ/(kmol*K)

Homework Equations


EQ 3.48: Q/nR=α(T2-T1)+1/2β(T22-T12)+1/3γ(T23-T13)

The Attempt at a Solution


I know all the α,β,γ values for O2, N2, and CO2.
I know n=8 moles.
but I don't know the values of α, β, and γ for the mixture.
I thought of using a molar ratio of each element and multiplying that times each α, β, and γ then adding them all together but I wasn't sure if this was correct
 
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  • #2
Yes, that's correct. Approximating the mixture as an ideal gas, the three components behave independently.
 
  • #3
You will need to know the initial temperature.

Just to follow up on Chester's point,

##\Delta Q = \Delta U = (n_1C_{v1}+n_2C_{v2}+n_3C_{v3})\Delta T = (n_1+n_2+n_3)C_{vmix}\Delta T##

AM
 

FAQ: Final temperature real gas behaving ideally

What is the final temperature of a real gas behaving ideally?

The final temperature of a real gas behaving ideally depends on its initial temperature, pressure, and volume. It can be calculated using the ideal gas law, which states that the product of pressure and volume is directly proportional to the product of the number of moles and temperature. Therefore, the final temperature can vary depending on the conditions of the gas.

How does a real gas behave ideally?

A real gas behaves ideally if it follows the ideal gas law, which assumes that the gas particles have zero volume and do not interact with each other. This means that the pressure and volume of the gas are directly proportional to the temperature and number of gas particles. In reality, real gases deviate from this behavior at high pressures and low temperatures.

Can a real gas behave ideally?

In most cases, real gases cannot behave ideally due to the presence of intermolecular forces and the finite size of gas particles. However, at low pressures and high temperatures, real gases can approximate ideal gas behavior. This is why the ideal gas law is often used as an approximation in many scientific calculations.

What is an example of a real gas behaving ideally?

An example of a real gas behaving ideally is a gas at low pressure and high temperature, such as air in a hot air balloon. At these conditions, the gas particles are far apart and have high kinetic energy, making them behave similarly to an ideal gas. However, as the pressure increases or the temperature decreases, the gas will deviate from ideal gas behavior.

What are the limitations of using the ideal gas law for real gases?

The ideal gas law is only applicable to ideal gases, which do not exist in reality. Therefore, it is only an approximation for real gases. Additionally, the ideal gas law assumes that the gas particles have no volume and do not interact with each other, which is not the case for real gases. Therefore, at high pressures and low temperatures, the ideal gas law may not accurately predict the behavior of real gases.

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