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Homework Statement
Homework Equations
Z = √(XC2 + XL2)
XL = 2πƒL
XC = 1 / 2πƒC
I = V/Z
The Attempt at a Solution
First off, thank you for all of the help this semester. I'm sure you'll be seeing questions from me in the spring also. Here is how I'm thinking about this problem:
1. Using the above equations, I find the reactances of the inductor and capacitor to be 3141.59Ω and 1.59Ω, respectively.
2. Add: XL + (-XC) = 3140Ω = Z
Note: I used -XC because on a graph the capacitor's reactance would be a downward pointing vector. However, no matter if I add or subtract these reactances the final current would be equivalent since 1.59Ω is much, much smaller than 3141.59Ω.
I decided that I could use superposition. So first equation: I = 1.2V / 3140 = .382mA. Second equation: 0.8V / 3140 = .255mA
4. Now I superimpose them. Since the 1.2V source moves rightward and the 0.8V source moves leftward, I did the following:
→ ← →
.382 - .255 = .127mA5. My final result seems to be off. Relative to the voltage through the 1.2V source, here is the graph:
One thing I noticed I did wrong is that the current of .127mA would be present when at the voltage peak of a single source circuit. Since I have 2 voltage sources the way I compared my current to my voltage peak doesn't make sense.
If someone could highlight where I am going wrong I would be very appreciative. The finals are on Wednesday and I've been studying for 6hrs so I'm going to head to bed and check on this in the AM. Thanks :)