- #1
Dell
- 590
- 0
find the values for A,B such that
Limx->infinity x*((x3+x2+ax)(1/3)-(x3-bx)(1/3)) = 3
what i thought was
t=1/x
Limt->0 1/t*((1/t3+1/t2+a/t)(1/3)-(1/t3-b/t)(1/3)) = 3
Limt->0 1/t*((1/t3+1/t2+a/t)(1/3)-(1/t3-b/t)(1/3)) = 3
since here we have 0/0 i can use l'hopital's law, but it looks like its going to get really ugly whith too manu terms,
also how can i solve for both A and B when i have only one equation
Limx->infinity x*((x3+x2+ax)(1/3)-(x3-bx)(1/3)) = 3
what i thought was
t=1/x
Limt->0 1/t*((1/t3+1/t2+a/t)(1/3)-(1/t3-b/t)(1/3)) = 3
Limt->0 1/t*((1/t3+1/t2+a/t)(1/3)-(1/t3-b/t)(1/3)) = 3
since here we have 0/0 i can use l'hopital's law, but it looks like its going to get really ugly whith too manu terms,
also how can i solve for both A and B when i have only one equation