dola said:
dola said:
To find a nonzero vector with a specific initial point, you can use the formula u = ai + bj + ck, where a, b, and c are the x, y, and z coordinates of the initial point, respectively. In this case, the initial point is P(-1, 3, -5), so the vector would be u = -1i + 3j - 5k.
No, a vector with an initial point of (-1, 3, -5) cannot have a magnitude of 0. A nonzero vector by definition has a magnitude greater than 0, and the initial point given in this question is a fixed point in space, which cannot have a magnitude.
A vector with an initial point is a directed line segment in space, where the initial point is the starting point of the vector and the endpoint is determined by the direction and magnitude of the vector. It is used to represent displacement, velocity, and force, among other physical quantities in mathematics and physics.
No, there are infinitely many nonzero vectors with an initial point of (-1, 3, -5). This is because for any point in 3D space, there are infinite possible directions and magnitudes that a vector can have. Therefore, there are infinite possible vectors that can have (-1, 3, -5) as their initial point.
No, a vector with an initial point at the origin (0, 0, 0) cannot be considered a nonzero vector. This is because the magnitude of the vector, which represents its length, would be 0. A nonzero vector, by definition, has a magnitude greater than 0.