Given cot(gamma) = 4/3, the triangle formed has sides AC = 4, BC = 3, and AB = 5, which is derived using the Pythagorean theorem. From this, the sine, cosine, and tangent functions can be calculated: sin(gamma) = 3/5, cos(gamma) = 4/5, and tan(gamma) = 3/4. Additionally, the cosecant, secant, and cotangent functions are found to be csc(gamma) = 5/3, sec(gamma) = 5/4, and cot(gamma) = 4/3, confirming the initial condition. All five remaining trigonometric functions of gamma have been successfully determined. This solution illustrates the relationship between the cotangent and the other trigonometric functions.
