- #1
tconlon33
- 7
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Hello people, thanks for reading. I am glad you are checking out my problem. Basically I need to confirm a "theory/formula" that my boss had written down from a decade ago declaring how much water (roughly) would be needed to cool Slag from steel making process to below boiling.
PROBLEM: Figure out how much H20 is needed to cool Slag down to 212°C
GIVEN:
MASS: 2000 lbs. or 1 ton or 907.185 kg
HEAT CAPACITY
Carbon Steel: 0.12 (Kcal/Kg°)C
Heat of H20 Vaporization (Enthalpy): 2260 J/g°C
TEMPERATURE
T1: 2200°F or 1104.4°C
T2: 212°F or 100°C
ΔT: 1104.44 °C
CONVERSIONS
1 Kcal = 4.184 Kilajoules
1 Gallon = 3.785 Kg
FORMULA
(MASS) (HEAT CAPACITY) (ΔTEMPERATURE) = Energy Removed From Slag
(907.168 Kg) (0.12 Kcal/Kg°)C (1104.44°)C
(907.168 Kg) (0.12 Kcal/Kg°)C (1104.44°)C
(120229.5151 Kcal)
(120229.5151 Kcal) 4.184 Kj
1 1 Kcal
503,040.2912 Kj = Energy Needed to be Removed from Slag
503,040.2912 Kj 503,040,291 Joules
503,040,291 J 1
1 2.260 J/g°C
(222584199.6 Grams) in H20 222,584 Kg
222,584 Kg 1 gallon
1 3.785 Kg
58806.86 Gallons of Water
Does anyone think I am close to the right solution? Yet again this need not be an extremely precise calculation. I really just want a ballpark that has been found using good math
PROBLEM: Figure out how much H20 is needed to cool Slag down to 212°C
GIVEN:
MASS: 2000 lbs. or 1 ton or 907.185 kg
HEAT CAPACITY
Carbon Steel: 0.12 (Kcal/Kg°)C
Heat of H20 Vaporization (Enthalpy): 2260 J/g°C
TEMPERATURE
T1: 2200°F or 1104.4°C
T2: 212°F or 100°C
ΔT: 1104.44 °C
CONVERSIONS
1 Kcal = 4.184 Kilajoules
1 Gallon = 3.785 Kg
FORMULA
(MASS) (HEAT CAPACITY) (ΔTEMPERATURE) = Energy Removed From Slag
(907.168 Kg) (0.12 Kcal/Kg°)C (1104.44°)C
(907.168 Kg) (0.12 Kcal/Kg°)C (1104.44°)C
(120229.5151 Kcal)
(120229.5151 Kcal) 4.184 Kj
1 1 Kcal
503,040.2912 Kj = Energy Needed to be Removed from Slag
503,040.2912 Kj 503,040,291 Joules
503,040,291 J 1
1 2.260 J/g°C
(222584199.6 Grams) in H20 222,584 Kg
222,584 Kg 1 gallon
1 3.785 Kg
58806.86 Gallons of Water
Does anyone think I am close to the right solution? Yet again this need not be an extremely precise calculation. I really just want a ballpark that has been found using good math