Find an f that satisfies these statements - Deltas and Epsilons

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To find a function f that satisfies the condition where the limit as x approaches a does not equal L, one must understand that for every ε>0, there exists a δ>0 such that there are x values close to a where |f(x)-L|<ε. However, the key point is that this condition can hold true without the limit existing, meaning there can be some ε for which no corresponding δ can be found. An example of this scenario is the function f(x) = 1/x as x approaches 0, which does not converge to a limit. Clarifying the quantification of ε and δ is crucial to grasping the concept.
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Homework Statement



Find an f that satisfies this statement:
<br /> \lim_{x\rightarrow a} f(x)≠L<br />

∀ε&gt;0 ∃δ&gt;0∃ x:0&lt;|x-a|&lt;δ AND |f(x)-L|&lt;ε

Homework Equations

The Attempt at a Solution



I'd just like a small hint on how I would go about finding a function. How can there be a delta for every epsilon and the rest of the statement is fulfilled, but there is no limit? The notation's just a tad confusing.
 
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Numnum said:

Homework Statement



Find an f that satisfies this statement:
<br /> \lim_{x\rightarrow a} f(x)≠L<br />

∀ε&gt;0 ∃δ&gt;0∃ x:0&lt;|x-a|&lt;δ AND |f(x)-L|&lt;ε

Homework Equations




The Attempt at a Solution



I'd just like a small hint on how I would go about finding a function. How can there be a delta for every epsilon and the rest of the statement is fulfilled, but there is no limit? The notation's just a tad confusing.

You aren't quantifying this right. There just has to be one epsilon without any corresponding delta. lim x->0 x isn't equal to 1. Prove it.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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