- #1
drillman9
- 7
- 0
Hi
I would really appreciate it if anybody could lead me in the right direction on this one...
|A| = |B|
|A+B| = 100|A-B|
I need to find the angle between A and -B for the statement to be true.
Using cosine laws I've come up with the following eqn:
|A+B| = 100|A-B|
2|A|^2 + (2|A|^2)(cosx) = 100[2|A|^2 - (2|A|^2)(cosx)]
I applied these cosine laws to the isosceles triangles
I'm not looking for the answer, I'm just looking to get some guidelines on solving for x, the angle.
Thanks so much
note: A and B are vectors.
I would really appreciate it if anybody could lead me in the right direction on this one...
|A| = |B|
|A+B| = 100|A-B|
I need to find the angle between A and -B for the statement to be true.
Using cosine laws I've come up with the following eqn:
|A+B| = 100|A-B|
2|A|^2 + (2|A|^2)(cosx) = 100[2|A|^2 - (2|A|^2)(cosx)]
I applied these cosine laws to the isosceles triangles
I'm not looking for the answer, I'm just looking to get some guidelines on solving for x, the angle.
Thanks so much
note: A and B are vectors.
Last edited: