Find center and radii of a circule

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In summary, the conversation discusses finding the center and radii of a sphere given the equation 2x^2+2y^2+2z^2+x+y+z=9. The solution involves dividing out the 2, completing the square, and solving for the right side. The center is found to be C{-1/4,-1/4,-1/4} and the radii is (5 sqrt 3) / 4.
  • #1
lucky strike
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Homework Statement



2x^2+2y^2+2z^2+x+y+Z=9
find center and radii of the sphere

Homework Equations



moving like terms yeilds

2x^2 + x + _ + 2y^2 + y + _ + 2z^2 + z + _ = 9

The Attempt at a Solution



divide out the 2 yeilds

2[ x^2 + 1/2x + _ + y^2 + 1/2y + _ + z^2 + 1/2z + _ ] = 9/2

complete the square

1/2 / 2 = (1/4)^2 = 1/16

adding term in

x^2 + 1/2x + 1/16 + y^2 + 1/2y + 1/16 + z^2 + 1/2z + 1/16 = 9/2 + 3/16

solving right side

9/2 + 3/16 = 72/16 + 3/16 = 75/16

factoring left side

(x + 1/4)^2 + (y + 1/4)^2 + (z + 1/4)^2

solving

center = C{-1/4,-1/4,-1/4}
radii = sqrt of 75/16 = (5 sqrt 3) / 4

whoot!
 
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  • #2
lucky strike said:

Homework Statement



2x^2+2y^2+2z^2+x+y+Z=9
find center and radii of the sphere

Homework Equations



moving like terms yeilds

2x^2 + x + _ + 2y^2 + y + _ + 2z^2 + z + _ = 9

The Attempt at a Solution



divide out the 2 yeilds

2[ x^2 + 1/2x + _ + y^2 + 1/2y + _ + z^2 + 1/2z + _ ] = 9/2
Either drop the "2" at the start or the "2" in "9/2"- you can't have them both!

complete the square

1/2 / 2 = (1/4)^2 = 1/16

adding term in

x^2 + 1/2x + 1/16 + y^2 + 1/2y + 1/16 + z^2 + 1/2z + 1/16 = 9/2 + 3/16
Okay, now that leading "2" is gone.

solving right side

9/2 + 3/16 = 72/16 + 3/16 = 75/16

factoring left side

(x + 1/4)^2 + (y + 1/4)^2 + (z + 1/4)^2

solving

center = C{-1/4,-1/4,-1/4}
radii = sqrt of 75/16 = (5 sqrt 3) / 4

whoot!
Looks good to me!
 
  • #3


Great job on finding the center and radii of the sphere! Your method of completing the square was a great approach to solving this problem. Keep up the good work!
 

FAQ: Find center and radii of a circule

What is the center of a circle?

The center of a circle is the point that is equidistant from all points on the circumference of the circle. It is often denoted as the point (h, k) in the standard form equation of a circle.

How do you find the center of a circle?

To find the center of a circle, you can use the standard form equation of a circle, which is (x - h)^2 + (y - k)^2 = r^2. The values of h and k in this equation represent the coordinates of the center point.

What is the radius of a circle?

The radius of a circle is the distance from the center of the circle to any point on the circumference. It is usually denoted as "r" in the standard form equation of a circle.

How do you find the radius of a circle?

The radius of a circle can be found by using the Pythagorean theorem, where r = √(x^2 + y^2). This can also be determined by measuring the distance from the center to any point on the circumference.

Can the center and radius of a circle be determined from a graph?

Yes, the center and radius of a circle can be determined from a graph. The center will be the point where the x and y coordinates intersect, and the radius can be found by measuring the distance from the center to any point on the circumference.

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