Find Cos2A: sinA=-1/3, pi<A<3pi/2

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To find Cos2A given sinA = -1/3 and the interval pi ≤ A ≤ 3pi/2, it is effective to use the identity cos2A = 1 - sin²A. Since sinA = -1/3, calculate sin²A to get 1/9. Substituting this value into the identity gives cos2A = 1 - 1/9, resulting in cos2A = 8/9. This approach simplifies the problem without needing to find the specific angles where sinA equals -1/3. The final result is cos2A = 8/9.
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Homework Statement


Find Cos2A if sinA= -1/3 and pi< (or equal to) A < (or equal to) 3pi/2


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The Attempt at a Solution


Do i use sin-1 to find when sin equals -1/3
 
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Yes, you can do that, that's the simple way. Take note of where your answer occurs as there are 2 points where sin(x) = -1/3. The question tells you the domain of A.
 
That's the hard way. The easy way is to use the a identity that expresses cos(2A) in terms of sin(A).
 
You should use the identity cos2A = cos2A - sin2A and

cos2A = 1 - sin2A

Regards.
 

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