Find Cos2A: sinA=-1/3, pi<A<3pi/2

  • Thread starter Centurion1
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In summary, to find cos2A when sinA= -1/3 and pi< (or equal to) A < (or equal to) 3pi/2, you can either use the formula cos2A = cos2A - sin2A or take the inverse sine of -1/3. It is important to note the domain of A, as there are two possible solutions.
  • #1
Centurion1
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Homework Statement


Find Cos2A if sinA= -1/3 and pi< (or equal to) A < (or equal to) 3pi/2


Homework Equations





The Attempt at a Solution


Do i use sin-1 to find when sin equals -1/3
 
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  • #2
Yes, you can do that, that's the simple way. Take note of where your answer occurs as there are 2 points where sin(x) = -1/3. The question tells you the domain of A.
 
  • #3
That's the hard way. The easy way is to use the a identity that expresses cos(2A) in terms of sin(A).
 
  • #4
You should use the identity cos2A = cos2A - sin2A and

cos2A = 1 - sin2A

Regards.
 

FAQ: Find Cos2A: sinA=-1/3, pi<A<3pi/2

What is the value of cos2A?

The value of cos2A is -8/9.

How is cos2A related to sinA?

Using the Pythagorean identity, cos2A can be expressed as 1-2sin^2A. So, for the given value of sinA, cos2A can be calculated as -8/9.

What is the range of possible values for A?

The given condition, pi

How can the value of cos2A be verified?

The value of cos2A can be verified by using a scientific calculator or by manually calculating the value using the double-angle formula for cosine.

What is the significance of finding cos2A in this problem?

Finding cos2A in this problem is significant because it allows for further calculations and analysis of the given trigonometric function. It also provides insight into the relationship between sine and cosine functions.

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