- #1
karush
Gold Member
MHB
- 3,269
- 5
$\textsf{a. Find the determinants by row reduction in echelon form.}$
$$\left|
\begin{array}{rrr}
1&5&-6\\ -1&-4&4 \\ -2&-7 & 9
\end{array}
\right|$$
ok i multiplied $r_1$ by 1 and added it to $r_2$ to get
$$\left|
\begin{array}{rrr}
1&5&-6\\ 0&1&-2 \\ -2&-7 & 9
\end{array}
\right|$$
but how do you get $0 \,0 \, r_3 c_3$
so it will be in echelon form?
the book answer is $3$
$$\left|
\begin{array}{rrr}
1&5&-6\\ -1&-4&4 \\ -2&-7 & 9
\end{array}
\right|$$
ok i multiplied $r_1$ by 1 and added it to $r_2$ to get
$$\left|
\begin{array}{rrr}
1&5&-6\\ 0&1&-2 \\ -2&-7 & 9
\end{array}
\right|$$
but how do you get $0 \,0 \, r_3 c_3$
so it will be in echelon form?
the book answer is $3$