Find Equation of Ellipse at (1,2) & (1,8), Minor Axis Length 4

In summary, the equation of the ellipse with center (1,2) and vertex at (1,8) and minor axis length of 4 is $\frac{(x-1)^2}{16} + \frac{(y-2)^2}{36}=1$, with a semi-major axis length of 6 and a semi-minor axis length of 2.
  • #1
schooler
4
0
Find equation for center at (1,2) and vertex at (1,8) and Minor axis length of 4?
 
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  • #2
Hello, schooler!

Did you make a sketch?


Find equation of the ellipse with center (1,2),
and vertex at (1,8) and minor axis length of 4.
Code:
          |
          |   *(1,8)
          |   :
          |   :
          |   :6
          |   :
          |   :   2
      * . | . + . . . *
          |   :(1,2)
    - - - + - : - - - - -
          |   :
          |   :
          |   :
          |   *
          |
We have enough information to write the equation.

. . [tex]\frac{(x-1)^2}{4} + \frac{(y-2)^2}{36} \;=\;1[/tex]
 
  • #3
schooler said:
Find equation for center at (1,2) and vertex at (1,8) and Minor axis length of 4?

Hello, schooler! :D

We do ask that you show what you have tried so our helpers can see where you are stuck and can help get you unstuck. If you simply post a problem with no work shown, we don't really know how to help, other than perhaps give you hints you have already tried which wastes your time and the time of the helper. Most of our helpers are not going to just work the problem for you, because this does not really get you involved in the process and maximize the "learning moment."
 
  • #4
soroban said:
[tex]\frac{(x-1)^2}{4} + \frac{(y-2)^2}{36} \;=\;1[/tex]
This should be
\[
\frac{(x-1)^2}{16} + \frac{(y-2)^2}{36}=1
\]
 
  • #5
Hello, Evgeny!

The semi-major axis has length 6.
Hence: [tex]a = 6.[/tex]

The minor axis has length 4.
The semi-minor axis has has length 2.
Hence: [tex]b = 2.[/tex]

 
  • #6
Sorry, you are right. I read it as the minor semi-axis has length 4.
 

FAQ: Find Equation of Ellipse at (1,2) & (1,8), Minor Axis Length 4

What is an ellipse?

An ellipse is a type of geometric shape that is similar to a circle, but has two distinct focal points instead of one. It is formed by the intersection of a cone and a plane, resulting in a curved oval shape.

How can I find the equation of an ellipse with given points and minor axis length?

To find the equation of an ellipse with given points and minor axis length, you can use the standard form of the equation: (x-h)^2/a^2 + (y-k)^2/b^2 = 1. Here, (h,k) represents the coordinates of the center of the ellipse, a represents the length of the semi-major axis, and b represents the length of the semi-minor axis. You can then plug in the given points and minor axis length to solve for the remaining variables and determine the equation.

What do the given points represent in the equation of an ellipse?

The given points represent two points on the ellipse's circumference. These points, along with the center point, determine the size and orientation of the ellipse.

How is the minor axis length measured in an ellipse?

The minor axis length in an ellipse is measured as the distance between the two furthest points on the ellipse's shorter axis. It is also known as the semi-minor axis length, as it is half of the total length of the minor axis.

Can the equation of an ellipse be written in other forms?

Yes, the equation of an ellipse can also be written in the general form Ax^2 + By^2 + Cxy + Dx + Ey + F = 0, where A, B, and C represent the coefficients of the x^2, y^2, and xy terms, respectively. However, the standard form is the most commonly used and easier to work with.

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