Find equilibrium bond potential, given energy as a function of atomic separation

In summary, the conversation discusses finding the equilibrium bond length for an ionic crystal by differentiating the total cohesive energy function and setting it to zero. However, the attempt at a solution resulted in a wrong answer, possibly due to a problem with the substitution. Upon closer examination, it was discovered that the given question was a misprint.
  • #1
knowlewj01
110
0

Homework Statement



Given that the total cohesive energy, U, in an ionic crystal as a function of nearest neighbor distance, R, between two ions +e and -e is given by:

[itex]U(R) = \frac{A}{R^n} - \frac{\alpha e^2}{4 \pi \epsilon R}[/itex]

show that at equilibrium:

[itex] U(R) = \frac{\alpha e^2}{4 \pi \epsilon R}(1 - \frac{1}{n})[/itex]

Homework Equations



differentiate U with respect to R and set to zero to find the equilibrium bond length and substitute it into the origonal formula. I think this is the right way to do it but i keep getting the wrong answer, here is my best attempt:

The Attempt at a Solution



[itex]U(R) = \frac{A}{R^n} - \frac{\alpha e^2}{4 \pi \epsilon R}[/itex]

differentiate w.r.t. R and equate to 0:

[itex]\frac{dU}{dR} = 0 = -\frac{n A}{R^{n+1}} + \frac{\alpha e^2}{4 \pi \epsilon R^2}[/itex]

now rearrange to get:

[itex]\frac{n A}{R^{n+1}} = \frac{\alpha e^2}{4 \pi \epsilon R^2}[/itex]

Multiply through by R and divide through by n:

[itex]\frac{A}{R^n} = \frac{\alpha e^2}{4 n \pi \epsilon R}[/itex]

Notice that the term [itex]\frac{A}{R^n}[/itex] appears in the original formula, so substitute to get:

[itex] U(R) = \frac{\alpha e^2}{4 \pi \epsilon R}(\frac{1}{n} - 1)[/itex]

the 1/n and 1 are the wrong way round, i have a feeling its a problem with my substitution but i can't see it, anyone have any ideas?

//Edit: I have put in the correct latex code so you can see my calculations ;)
 
Last edited:
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  • #2
We cannot read your equations. Please try to use LateX.
 
  • #3
ah, ok sorry about that ill try edit it
 
  • #4
Nevermind, I just found out that this question was a misprint making it impossible. Thanks
 
  • #5


Your approach is correct, but there is a small error in your algebra. When you rearranged the equation, you forgot to include the "n" in the denominator on the right side. It should be:

\frac{A}{R^n} = \frac{\alpha e^2}{4 n \pi \epsilon R}

Then, when you substitute into the original formula, you get:

U(R) = \frac{\alpha e^2}{4 \pi \epsilon R}(\frac{1}{n} - \frac{1}{n})

Simplifying, this becomes:

U(R) = \frac{\alpha e^2}{4 \pi \epsilon R}(\frac{1}{n} - 1)

which is the correct answer.
 

FAQ: Find equilibrium bond potential, given energy as a function of atomic separation

1. What is equilibrium bond potential?

Equilibrium bond potential is the minimum energy state of a bonded system, where the attractive and repulsive forces between atoms are balanced, resulting in a stable bond length.

2. How is energy related to atomic separation in a bonded system?

Energy is a function of atomic separation in a bonded system, meaning the energy changes as the distance between atoms changes. Atoms that are too close or too far apart will have higher energy, while atoms at the equilibrium bond length will have the lowest energy.

3. How do you find the equilibrium bond potential?

The equilibrium bond potential can be found by plotting the energy as a function of atomic separation and identifying the point where the energy is minimum. This point represents the equilibrium bond length and potential.

4. What factors affect the equilibrium bond potential?

The equilibrium bond potential is affected by the type of atoms involved, their charges, and the strength of their bond. It can also be influenced by external factors such as temperature and pressure.

5. How is the equilibrium bond potential useful in understanding chemical bonds?

The equilibrium bond potential provides insight into the stability and strength of a chemical bond. It helps in understanding the factors that contribute to the formation and breaking of bonds, and can aid in predicting the properties and behavior of molecules.

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