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doanta
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Homework Statement
An equilibrium ore mixture has an atomic ratio for [tex]\frac{U-235}{Pa-231} = 3.04x10^{6}[/tex]
Find the half-life of U-235 from the data. The known half-life for Pa-231 is [tex]3.28x10^{4}[/tex] years
Homework Equations
For secular equilibrium
[tex]\frac{\lambda_{2} N_{2}}{\lambda_{1} N_{1}} = 1
[/tex]
[tex]\lambda = \frac{Ln(2)}{Half-Life}[/tex]
The Attempt at a Solution
[tex]\lambda_{Pa-231} = \frac{Ln(2)}{3.28x10^{4}} = 2.113x10^{-5}y^{-1}[/tex]
[tex]\frac{2.113x10^{-5}y^{-1}}{\lambda_{1}} = 3.04x10^{6}[/tex]
[tex]\lambda_{1} = 6.951x10^{-12}[/tex]
[tex]T_{1/2_{U}} = \frac{Ln(2)}{6.951x10^{-12}}[/tex]
[tex]T_{1/2_{U}} = 9.97x10^{10}yrs[/tex]
Am I taking the right approach? I know the half life of U-235 is only [tex]7.04x10^{8}[/tex] and my answer is pretty far off.