- #1
Dustinsfl
- 2,281
- 5
On $U=\mathbb{C}-\{0\}$, find a holomorphic function $f=u+iv$.
$$
u(x,y) = \frac{y}{x^2+y^2}
$$
u is harmonic on U
Let g be a primitive for f on U.
write $g=\varphi +i\psi$.
Then $\varphi_x = u$.
$$
\varphi_{xy} = \psi_{xy} = \frac{x^2-y^2}{(x^2+y^2)^2}
$$
So I can integrate the above with respect to x and find a function with the constant of integration being some h(y).
Then I would have v and I would have found my function f correct?
So I found $f$ to be
$$
f(z) = u + iv = \frac{y}{x^2 + y^2} + i\left[\frac{x}{x^2 + y^2} + h(y)\right].$$
Correct?
$$
u(x,y) = \frac{y}{x^2+y^2}
$$
u is harmonic on U
Let g be a primitive for f on U.
write $g=\varphi +i\psi$.
Then $\varphi_x = u$.
$$
\varphi_{xy} = \psi_{xy} = \frac{x^2-y^2}{(x^2+y^2)^2}
$$
So I can integrate the above with respect to x and find a function with the constant of integration being some h(y).
Then I would have v and I would have found my function f correct?
So I found $f$ to be
$$
f(z) = u + iv = \frac{y}{x^2 + y^2} + i\left[\frac{x}{x^2 + y^2} + h(y)\right].$$
Correct?
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