- #1
ILoveBaseball
- 30
- 0
Find the length of parametrized curve given by
[tex]x(t) = 0t^3 +12t^2 - 24t[/tex],
[tex]y(t) = -4t^3 +12t^2+0t[/tex],
where t goes from zero to one.
Hint: The speed is a quadratic polynomial with integer coefficients.
it's an arclength question right?
x' = 24*t-24
y' = -12*t^2+24*t
[tex]\int_{0}^{1} \sqrt{(24*t-24)^2 + (-12*t^2+24*t)^2}[/tex]
i get 6.49 when i use a math program to integrate it which is incorrect. anyone know where i went wrong?
[tex]x(t) = 0t^3 +12t^2 - 24t[/tex],
[tex]y(t) = -4t^3 +12t^2+0t[/tex],
where t goes from zero to one.
Hint: The speed is a quadratic polynomial with integer coefficients.
it's an arclength question right?
x' = 24*t-24
y' = -12*t^2+24*t
[tex]\int_{0}^{1} \sqrt{(24*t-24)^2 + (-12*t^2+24*t)^2}[/tex]
i get 6.49 when i use a math program to integrate it which is incorrect. anyone know where i went wrong?