Find Limit of Fibonacci Sequence | Determine L

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In summary, the conversation discusses finding the limit of a sequence to a number when not given any numbers to work with. The Fibonacci sequence is used to demonstrate finding the limit, and the conversation delves into using the quadratic equation to solve for L.
  • #1
Punkyc7
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Let f[itex]_{n}[/itex] be the Fibonacci sequence and let [itex]x_{n}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex]. Given that lim[itex](x_{n}[/itex])=L exist determine L.

Ok so I know that the limit is [itex]\frac{1+\sqrt{5}}{2}[/itex] from previous experience with the sequence, but I am not sure how do you show that without writing out a lot of terms and then noticing what I all ready know it is. How do you find the limit of a sequence to a number if your not given any numbers to work with?
 
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  • #2
Hi Punkyc7 ! :smile:

If there is a limit, then you can assume that xn = xn-1 :wink:
 
  • #3
true, but how do you ever get a number when you are dealing with f[itex]_{n}[/itex] and f[itex]_{n+1}[/itex]. How can you just make a jump and say there is a [itex]\sqrt{5}[/itex] in there
 
  • #4
Punkyc7 said:
How can you just make a jump and say there is a [itex]\sqrt{5}[/itex] in there

quadratic equation? :wink:
 
  • #5
Ok I am not sure how you got there but this is what I have so farlet [itex]x_{n}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex] and let lim[itex](x_{n}[/itex])=L. From here is where I get stuck. I know that every sub sequence of a convergent sequence converges to the same number by some theorem, but I am not sure how that is at all helpful.

Would you do something like
[itex]x_{n}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex]
[itex]x_{n-1}[/itex] = [itex]f_{n}[/itex]/[itex]f_{n-1}[/itex]
 
  • #6
put xn = xn-1
 
  • #7
Ok so you get

= [itex]f_{n}[/itex]/[itex]f_{n-1}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex]

I think I see where you got the quadratic equation now

[itex]f_{n}[/itex] ^2= [itex]f_{n-1}[/itex] [itex]f_{n+1}[/itex]=[itex]f_{n}[/itex] ^2 - [itex]f_{n-1}([/itex] [itex]f_{n+1}[/itex])to use the quadratic equation is this [itex]f_{n-1}([/itex] [itex]f_{n+1}[/itex]) considered b or c?

and that doesn't look very pretty to solve...
 
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  • #8
erm :redface:

you'll also need fn+1 = … ? :wink:
 
  • #9
Ok

[itex]f_{n+1}[/itex]=[itex]\frac{f_{n}}{f_{n-1}}[/itex]


[itex]f_{n}[/itex] ^2 - f[itex]_{n-1}[/itex]* [itex]\frac{f_{n}}{f_{n-1}}[/itex]

[itex]f_{n}[/itex] ^2 -[itex]f_{n}[/itex]=0

is that right?
 
  • #10
This is the Fibonacci sequence!

So fn+1 = ? :smile:
 
  • #11
oh so
f[itex]_{n+1}[/itex]= f[itex]_{n}[/itex] +f[itex]_{n-1}[/itex]


do I use that for f[itex]_{n+1}[/itex]
Also how do you know when to use what?
 
  • #12
Punkyc7 said:
do I use that for f[itex]_{n+1}[/itex]

yes … that should give you your quadratic equation :wink:
Also how do you know when to use what?

You're told it's a Fibonacci sequence, so you obviously have to use that information somewhere! :smile:

and now I'm off to bed :zzz:
 
  • #13
let [itex]x_{n}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex] and let lim[itex](x_{n}[/itex])=L. Since we know the sequence converges we can say

[itex]x_{n}[/itex] =[itex]x_{n-1}[/itex] Which Implies

= [itex]f_{n}[/itex]/[itex]f_{n-1}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex]

[itex]f_{n}[/itex] ^2= [itex]f_{n-1}[/itex] [itex]f_{n+1}[/itex]=[itex]f_{n}[/itex] ^2 - [itex]f_{n-1}([/itex] [itex]f_{n+1}[/itex])=0

[itex]f_{n}[/itex] ^2 - f[itex]_{n}[/itex]f[itex]_{n-1}[/itex]-f[itex]_{n-1}[/itex]^2=0How do you hammer this into the quadratic equation I am thinking the a=1 b=not sure c=not sure ? Also how do you get numbers from this when we don't have a single number?
 
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  • #14
Punkyc7 said:
let [itex]x_{n}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex] and let lim[itex](x_{n}[/itex])=L. Since we know the sequence converges we can say

[itex]x_{n}[/itex] =[itex]x_{n-1}[/itex] Which Implies

= [itex]f_{n}[/itex]/[itex]f_{n-1}[/itex] = [itex]f_{n+1}[/itex]/[itex]f_{n}[/itex]
...which also equals L:

[itex]\frac{f_n}{f_{n-1}} = \frac{f_{n+1}}{f_n} = L[/itex]

Now take this portion:
[itex]\frac{f_{n+1}}{f_n} = L[/itex]

Replace the numerator with its equivalent, and then rewrite as a sum of two fractions. A substitution can be made, and you will end up with an expression on the left side with NO f's. Soon you will see a quadratic equation in terms of L. Solve for L.
 

FAQ: Find Limit of Fibonacci Sequence | Determine L

What is the Fibonacci sequence?

The Fibonacci sequence is a mathematical sequence in which each number is the sum of the two preceding numbers. It starts with 0 and 1, and continues with 1, 2, 3, 5, 8, 13, 21, and so on.

Why is finding the limit of the Fibonacci sequence important?

Finding the limit of the Fibonacci sequence can help us understand the behavior of the sequence as it approaches infinity. This information can be useful in various fields such as finance, computer science, and biology.

How do you find the limit of the Fibonacci sequence?

To find the limit of the Fibonacci sequence, we can use the formula L = (1 + sqrt(5))/2, where L is the limit and sqrt(5) is the square root of 5. This formula is derived from the closed-form expression for the Fibonacci sequence.

What is the significance of the number "L" in finding the limit of the Fibonacci sequence?

The number "L" represents the limit of the Fibonacci sequence, which is the value that the sequence approaches as the number of terms increases. This value is also known as the golden ratio, and it has many interesting mathematical properties.

Can the limit of the Fibonacci sequence be negative or infinite?

No, the limit of the Fibonacci sequence cannot be negative or infinite. As the number of terms in the sequence increases, the values will approach the limit, but they will never exceed it. This is because the ratio of consecutive terms in the Fibonacci sequence approaches the golden ratio, which is a finite value.

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