- #1
lilkrazyrae
- 64
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A hydraulic jack has a pump piston of diameter 0.650cm, and a load piston of 4.40cm. Find the load which can be lifted if a force of 500.N is exerted on the pump piston.
Would you use the equation Fd=F(2)d(2)?
So (0.00650m)(500.N)=F(.0440m)
=73.9N
Would you use the equation Fd=F(2)d(2)?
So (0.00650m)(500.N)=F(.0440m)
=73.9N