Find Nearest Integer to $\dfrac{1}{k^3-2009}$

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In summary, the expression $\dfrac{1}{k^3-2009}$ represents a mathematical function that calculates the reciprocal of the difference between the cube of a given number, k, and the constant 2009. This function is useful for many mathematical and scientific applications, such as analyzing data and making approximations. To find the nearest integer to $\dfrac{1}{k^3-2009}$, rounding techniques or floor/ceiling functions can be used, but there are limitations to using this method, such as potential inaccuracies and not considering other factors. This function cannot be used to find the exact integer value, and other mathematical methods would need to be used for that purpose.
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anemone
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Let $k$ be the largest root of $x^4+1-2009x=0$. Find the nearest integer to $\dfrac{1}{k^3-2009}$.
 
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anemone said:
Let $k$ be the largest root of $x^4+1-2009x=0$. Find the nearest integer to $\dfrac{1}{k^3-2009}$.

x(x^3-2009) = -1

so 1/(x^3-2009) = - x

so we need to find the nearest integer to -x

now largest x is between 12.6 and 12.7(

method to compute x^4 = 2009 x, ignoring 1 and so x^3 = 2009 and then check )

so ans is - 13
 
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Well done, kaliprasad!:cool:
 

FAQ: Find Nearest Integer to $\dfrac{1}{k^3-2009}$

What does the expression $\dfrac{1}{k^3-2009}$ represent?

The expression $\dfrac{1}{k^3-2009}$ represents a mathematical function that calculates the reciprocal of the difference between the cube of a given number, k, and the constant 2009.

What is the significance of finding the nearest integer to $\dfrac{1}{k^3-2009}$?

Finding the nearest integer to $\dfrac{1}{k^3-2009}$ is useful in many mathematical and scientific applications, such as in analyzing data, solving equations, and making approximations.

How do you find the nearest integer to $\dfrac{1}{k^3-2009}$?

To find the nearest integer to $\dfrac{1}{k^3-2009}$, you can use rounding techniques, such as rounding up or down to the nearest whole number, or using the floor or ceiling functions.

What are the limitations of using $\dfrac{1}{k^3-2009}$ to find the nearest integer?

One limitation of using $\dfrac{1}{k^3-2009}$ to find the nearest integer is that it may not always result in an accurate approximation, especially for large values of k. Another limitation is that it only considers the reciprocal of the difference between k and 2009, and may not take into account other factors that may affect the nearest integer.

Can $\dfrac{1}{k^3-2009}$ be used to find the exact integer value?

No, $\dfrac{1}{k^3-2009}$ cannot be used to find the exact integer value, as it only calculates an approximation. To find the exact integer value, you would need to use other mathematical methods, such as solving the equation algebraically or using numerical methods.

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