No, [itex]1/\sqrt{x}[/itex] is not correct becausess_1985 said:Hi
The question asks to find out a function R--> R such that it is integrable, and its square is not.
Is f(x)=1/root x right?
The problem I thought was its only over an interval
Please help
thanks
An integrable function is a mathematical function that can be represented by an integral, which is a mathematical operation that can be used to calculate the area under a curve. In simpler terms, an integrable function is one that can be easily integrated or "added up" to find a total value.
R-->R refers to a function that takes a real number as an input and returns a real number as an output. In other words, the function operates on real numbers and produces real numbers as a result.
One example of an integrable function is f(x) = x^2. This function can be easily integrated to find the area under the curve, which in this case, is the area of a parabola. The integral of f(x) = x^2 is x^3/3 + C, where C is a constant.
A function is considered integrable if it meets certain criteria, such as being continuous and bounded on a given interval. This means that the function is defined and has a finite value at every point within the interval. Additionally, the function must also have a finite number of discontinuities within the interval in order to be integrable.
Integrable functions are essential in many areas of science, particularly in physics and engineering. They are used to calculate various physical quantities, such as work, energy, and momentum, and are also crucial in solving differential equations, which are commonly used to model natural phenomena. In addition, integrable functions play a key role in the development of advanced mathematical techniques and theories, making them a fundamental concept in the field of science.