- #1
yungman
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For a parallel polarization EM hitting the conductor boundary in an oblique angle. z axis is perpendicular to the boundary and point into the conductor. y-axis it out of the page which give x pointing up. Let the boundary surface by xy plane. With this:
The direction of the incident is:
[tex]\hat n_i \;=\; \hat x sin \theta_i + \hat z cos \theta_i \;\hbox { and direction of }\; \hat {E_i} \;= \hat x cos \theta_i - \hat z sin \theta_i [/tex]
I know
[tex] \hat {E_r} \;=\; \hat x cos \theta_i + \hat z sin \theta_i [/tex]
My question is how can I derive the direction of [itex] \vec {E_r}[/itex] by using formulas? I got this by looking at the reflection as I move the incident E towards the boundary...by drawing. I want to find this mathametically. Please help.
Thanks
Alan
The direction of the incident is:
[tex]\hat n_i \;=\; \hat x sin \theta_i + \hat z cos \theta_i \;\hbox { and direction of }\; \hat {E_i} \;= \hat x cos \theta_i - \hat z sin \theta_i [/tex]
I know
[tex] \hat {E_r} \;=\; \hat x cos \theta_i + \hat z sin \theta_i [/tex]
My question is how can I derive the direction of [itex] \vec {E_r}[/itex] by using formulas? I got this by looking at the reflection as I move the incident E towards the boundary...by drawing. I want to find this mathametically. Please help.
Thanks
Alan