Find Ratio ||v||/||u|| for u and v

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To find the ratio ||v|| / ||u|| for u = (−1, 2, 1) and v = (3, 3, 6), the norms are calculated as ||u|| = √(1^2 + 2^2 + 1^2) = √6 and ||v|| = √(3^2 + 3^2 + 6^2) = √54. The ratio is then computed as √54 / √6, which simplifies to 3. The initial calculation was confirmed to be correct, but there was a suggestion to verify the problem statement against the source material. It's important to ensure the problem is accurately represented before discussing it with the instructor.
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Homework Statement



For u = (−1, 2, 1) and v = (3, 3, 6) find the ratio ||v|| / ||u||

Homework Equations



|| u || = (u^2 + u2^2 + ...un^2)^.5

The Attempt at a Solution



I found the || u || to be 6^(1/2) and || v || to be 54^(1/2)
Therefore the ratio should be 54^(1/2) divided by 6^(1/2), which calculates to 3. It turns out the answer is incorrect. Can anyone show me where I went wrong?

Thanks.
 
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Nowhere.
 
I agree. The ratio is 3.

\frac{\sqrt{54}}{\sqrt{6}}~=~\frac{3\sqrt{6}}{\sqrt{6}}=~3
 
Okay thanks. I'll have to tell my instructor about it.
 
Before you do, make sure that the problem you posted here is exactly the same as in your book or wherever this problem came from.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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