Find Real Value of sin(i) Without i

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Therefore, there is no way to express the result of taking the real value of ##\sin(i)## in a nicer way.
  • #1
TheCanadian
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I am calculating a value and want to find the real value of sin(i). I can use series expansion and only take the terms without i (correct?) but is there any nicer way to express the result of taking the real value of sin(i)?
 
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  • #3
micromass said:

I used the imaginary exponentials and found ## \sin(i) = \frac{e^{-1} - e}{2i} ## but this seems purely imaginary...from the sum expansion of sin, it appeared that there were real values for the even power terms. Any advice you have for addressing what I am missing here since I'm looking for the real value would be great!
 
  • #4
Indeed, ##\sin(i)## is purely imaginary. If you look at the series expansion of ##\sin(i)##, you'll see that only ##i^{\text{odd power}}## appear in this expansion. And as you know, ##i^{\text{odd power}} = \pm i##.
 

FAQ: Find Real Value of sin(i) Without i

What is the real value of sin(i)?

The real value of sin(i) cannot be determined since the input i is an imaginary number and the sine function is only defined for real numbers.

How can I find the real value of sin(i)?

It is not possible to find the real value of sin(i) since i is an imaginary number and the sine function is only defined for real numbers.

Can the real value of sin(i) be approximated?

No, the real value of sin(i) cannot be approximated since i is an imaginary number and the sine function is only defined for real numbers.

Why can't we find the real value of sin(i)?

The real value of sin(i) cannot be found because it is undefined for imaginary numbers. The sine function is defined for real numbers only.

Is there a way to calculate the value of sin(i) without using i?

No, the value of sin(i) cannot be calculated without using i since it is an integral part of the input. Additionally, the sine function is only defined for real numbers.

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