Find Remainder with Fermat's Theorem

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Fermat's Little Theorem can be applied to find the remainder of a number when divided by another, particularly in the context of prime powers. The example given involves calculating the remainder of 52005 when divided by 4010, which factors into 2, 5, and 401. By finding integers a, b, and c for the congruences of 5^2005 modulo these factors, one can utilize the Chinese Remainder Theorem to combine the results. This method effectively simplifies the calculation of large powers modulo composite numbers. Understanding these theorems is essential for solving such remainder problems efficiently.
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How to use fermit's thereom in finding remainder of a number when divided by another number ?

(eg remainder of 52005 when divided by 4010 ?)
 
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How did you arrive at such a problem? Fermat's (little) theorem deals prime powers.
 
I'm assuming you don't know or don't want to use Euler's theorem.

Note 4010 = 2*5*401.

Can you find integers a,b,c such that
\begin{align*}<br /> 5^{2005} &amp;\equiv a \pmod 2 \\<br /> 5^{2005} &amp;\equiv b \pmod 5 \\<br /> 5^{2005} &amp;\equiv c \pmod {401}<br /> \end{align*}
? (perhaps using Fermat's little theorem)

If you can, then you can use these results and the Chinese remainder theorem to find 5^2005 modulo 2*5*401.
 
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