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rrab186
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The I/P converter is designed to produce the response 'A' in the graph attached. The balance equation of the system is:
Po=(Kc*y/A*x)*IinKc=2500Newton Amps (NA)
x+y=100mm
z=75 mm
A=5cm^2
Determine suitable values of y and x to give the response 'A' in the graph attached.
pressure must be entered into the equation in pascal and current in amps and all dimensions in metres
Po=(Kc*y/A*x)*Iin100000 pascals=(2500*y/0.0005meters^2*x)*0.02
100000/0.02 = (2500*y/0.0005*x)
5000000= (2500*y/0.0005*x)
It is at this point where i am stuck on how to continue and how to make x or y the subject of the equation.
Po=(Kc*y/A*x)*IinKc=2500Newton Amps (NA)
x+y=100mm
z=75 mm
A=5cm^2
Determine suitable values of y and x to give the response 'A' in the graph attached.
pressure must be entered into the equation in pascal and current in amps and all dimensions in metres
The Attempt at a Solution
Po=(Kc*y/A*x)*Iin100000 pascals=(2500*y/0.0005meters^2*x)*0.02
100000/0.02 = (2500*y/0.0005*x)
5000000= (2500*y/0.0005*x)
It is at this point where i am stuck on how to continue and how to make x or y the subject of the equation.
Attachments
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