Find ##\tan \theta ## in the form of ##a+b\sqrt {2}##

  • #1
chwala
Gold Member
2,748
387
Homework Statement
see attached.
Relevant Equations
Trigonometry - Add Maths
There is an error on ms ...unless i am missing something.

1715481924862.png


1715481969500.png
 
Physics news on Phys.org
  • #2
chwala said:
Homework Statement: see attached.
Relevant Equations: Trigonometry - Add Maths

There is an error on ms ...unless i am missing something.

View attachment 345058

View attachment 345059
Yes. There is an error.
 
  • Like
Likes chwala
  • #3
Showing the intermediate step where you group the radicals and simplify the denominator may help reveal the mistake.
 
  • Like
Likes chwala
  • #4
scottdave said:
Showing the intermediate step where you group the radicals and simplify the denominator may help reveal the mistake.
I saw the mistake ... just wanted to counter-check myself... Cheers man!

This is a question from an international curriculum paper and its highly unlikely for mistakes to be on ms ...
 
Last edited:
  • #5
chwala said:
I saw the mistake ... just wanted to counter-check myself... Cheers man!

This is a question from an international curriculum paper and its highly unlikely for mistakes to be on ms ...
What does ms stand for?
 
  • #6
scottdave said:
What does ms stand for?
It's chwala's abbreviation for "mark scheme."
 
  • Like
Likes chwala

FAQ: Find ##\tan \theta ## in the form of ##a+b\sqrt {2}##

What is the general approach to find ##\tan \theta## in the form of ##a+b\sqrt {2}##?

To find ##\tan \theta## in the form of ##a+b\sqrt {2}##, start by expressing the angle ##\theta## in terms of known angles or using trigonometric identities. You can utilize the tangent addition formulas or double angle formulas to simplify the expression. The goal is to manipulate the expression until it matches the desired form.

Can you provide an example of finding ##\tan \theta## in the form of ##a+b\sqrt {2}##?

Sure! For example, if ##\theta = 45^\circ + 15^\circ##, we can use the tangent addition formula: ##\tan(45^\circ + 15^\circ) = \frac{\tan 45^\circ + \tan 15^\circ}{1 - \tan 45^\circ \tan 15^\circ}##. Knowing that ##\tan 45^\circ = 1## and ##\tan 15^\circ = 2 - \sqrt{3}##, we can simplify this to find ##\tan \theta##. After simplification, it can be expressed in the form ##a + b\sqrt{2}##.

What values of ##a## and ##b## can be used in the expression ##a+b\sqrt{2}##?

The values of ##a## and ##b## are typically real numbers. The specific values depend on the angle ##\theta## being considered. For instance, if ##\tan \theta = 1 + \sqrt{2}##, then ##a = 1## and ##b = 1##. The goal is to match the expression to the required form based on the angle's tangent value.

Are there specific angles that yield ##\tan \theta## in the form of ##a+b\sqrt{2}##?

Yes, certain angles can yield this form. For example, angles like ##\theta = 15^\circ## or ##\theta = 75^\circ## can lead to expressions involving ##\sqrt{2}## when calculated. These angles often arise in problems involving special triangles or specific trigonometric identities.

How do I verify that my answer for ##\tan \theta## is correct?

To verify your answer, you can substitute the value of ##\tan \theta## back into the original problem or use a calculator to compute the tangent of the angle. Additionally, check if the result matches the form ##a + b\sqrt{2}## by simplifying your expression and comparing coefficients.

Back
Top