Find the apogee from v at perigee, perigee, g, and the radius of Earth

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To find the apogee and orbital period of a satellite given its perigee and tangential speed at perigee, one can utilize the gravitational constant g and the Earth's radius without needing the Earth's mass. The relationship between gravitational acceleration and the gravitational parameter allows for the calculation of the necessary parameters. By applying conservation of angular momentum, the maximum radius can be derived from the perigee and the velocities involved. The discussion clarifies that the gravitational parameter can be inferred from g and the Earth's radius, facilitating further calculations. This approach enables the completion of the problem without directly using the Earth's mass.
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Homework Statement


Satellite orbits the Earth and its perigee r_min and tangential speed at perigee v_pe are given. The problem says do not use mass of Earth in the calculation, and use the only the constants g = 9.8 and radius of Earth 6380 km. I'm supposed to find the apogee and orbital period, but not using mass of Earth makes things seem so complicated. And the formula for period itself has mass of Earth in it.

Homework Equations


where ecc is eccentricity
perigee = r_min + radius of Earth
r_max = (1+ecc)*r_min/(1-ecc)

The Attempt at a Solution


Since argular momentum is conserved,
m v_pe r_min = m v_ap r_max
=> r_max = v_pe r_min / v_ap
I tried to find v_ap, but that the formula has mass of Earth in it, so I can't use that.
Thank you
 
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But given g and the radius of the Earth you can infer the gravitational parameter ##\mu = GM_e##, right?
 
gneill said:
But given g and the radius of the Earth you can infer the gravitational parameter ##\mu = GM_e##, right?
So what you meant is
g = GM/r_earth^2 = μ/r_earth^2
=> g*r_earth^2 = μ ? That makes sense. Thank you.
 
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Natchanon said:
So what you meant is
g = GM/r_earth^2 = μ/r_earth^2
=> g*r_earth^2 = μ ? That makes sense. Thank you.
Yup. And so you can proceed with the rest of the usual basic orbital motion equation lexicon.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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