- #1
Carlo09
- 15
- 0
Ok it's my first time here and I was hoping to get some help on some questions I have been given. I am a first year chem eng and I'm finding the work pretty hard so any help at all will be useful, thanks.
I need to find the convective heat transfer coefficient, h for petrol using this equation:
hD/Lamdaf = 0.37 Re^0.6
so using information I am given:
D = 3mm = 0.003m
Lamdaf (thermal conductivity) = 0.145 w/m k
(M)=viscosity = 0.0006 Pa s
u=Velocity of petrol = 19.2 m/s
P=density of petrol = 737.22 kg/m^3
Ok so to calculate Re I am using: Dup/(M) = (0.003*19.2*737.22)/0.0006 = 70773.12
Is this correct so far?
Then I put this back into the equation and rearrange for h which I get to be =14533.475! w/m^2 k
Is this correct because it seems very big to me! if not please can someone point me into the right direction... thank you very much!
I need to find the convective heat transfer coefficient, h for petrol using this equation:
hD/Lamdaf = 0.37 Re^0.6
so using information I am given:
D = 3mm = 0.003m
Lamdaf (thermal conductivity) = 0.145 w/m k
(M)=viscosity = 0.0006 Pa s
u=Velocity of petrol = 19.2 m/s
P=density of petrol = 737.22 kg/m^3
Ok so to calculate Re I am using: Dup/(M) = (0.003*19.2*737.22)/0.0006 = 70773.12
Is this correct so far?
Then I put this back into the equation and rearrange for h which I get to be =14533.475! w/m^2 k
Is this correct because it seems very big to me! if not please can someone point me into the right direction... thank you very much!