Find the critical points of this function:

In summary, the conversation is discussing finding the critical points and determining whether they are local maxima, minima, or saddle points for the function f=\frac{1}{x} + \frac{1}{y} + xy. The attempt at a solution involves partially differentiating and setting the derivative to zero for both x and y, resulting in stationary points at (\frac{1}{y^2},\frac{1}{x^2}). However, it is mentioned that both conditions must be satisfied and the coordinates should be simplified.
  • #1
knowlewj01
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Homework Statement



Find the critical points of this function and determine wether they are local maxima, minima or saddle points...

[itex]f=\frac{1}{x} + \frac{1}{y} + xy[/itex]


The Attempt at a Solution



start off by partially differentiating and setting to zero for x and y:

[itex] \frac{\partial f}{\partial x}=\frac{\partial f}{\partial y}=0[/itex]


[itex]\frac{\partial f}{\partial x}= -\frac{1}{x^2} + y = 0[/itex]

[itex]\therefore y=\frac{1}{x^2}[/itex]


[itex]\frac{\partial f}{\partial y}= -\frac{1}{y^2} + x = 0[/itex]

[itex]\therefore x=\frac{1}{y^2}[/itex]

so:

[itex]\exists[/itex] a stationary point at [itex](\frac{1}{y^2},\frac{1}{x^2})[/itex]

using [itex] D = f_{xx}f_{yy} - (f_{xy})^2[/itex]




Does all of this look ok so far? because i do not get a definitive answer for where the critical point lies or any indication of it's nature.
 
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  • #2
No, both conditions have to be satisfied. Surely you can't leave your coordinates in terms of each other - they can and should then be simplified! So, it is a matter of solving the equations
[tex]y=\frac{1}{x^2}[/tex]
[tex]x=\frac{1}{y^2}[/tex]
simultaneously.
 

FAQ: Find the critical points of this function:

What are critical points?

Critical points are points on a graph where the derivative is equal to zero or does not exist. They are also known as stationary points or turning points and can indicate maximums, minimums, or inflection points on the graph.

How do you find the critical points of a function?

To find the critical points of a function, you must first take the derivative of the function and set it equal to zero. Then, solve for the variable to determine the x-values of the critical points. You should also check the second derivative to confirm whether the points are maximums, minimums, or inflection points.

Why are critical points important?

Critical points are important because they can tell us important information about a function, such as where it reaches its maximum or minimum values. They can also help us determine the concavity of a function and identify any potential points of inflection.

Can a function have multiple critical points?

Yes, a function can have multiple critical points. In fact, most functions have multiple critical points. These points can be located at different x-values and can indicate different behaviors of the function, such as local maximums and minimums.

How can critical points be used to optimize a function?

Critical points can be used to optimize a function by identifying the maximum or minimum value of the function. This information can be useful in real-world applications, such as maximizing profits or minimizing costs. Additionally, critical points can also help us determine the behavior of a function, which can aid in understanding and analyzing the function.

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