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dinospamoni
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Homework Statement
The power supply in the circuit shown has V(t) =
(120V)cos(ωt), where ω = 310 rad/s. Determine the current
flowing through the resistor at time t = 9.7 s, given R = 600 Ω,
C = 18 mF, and I(0) = 0 A. As a reminder, Kirkhoff’s voltage
law for this circuit (Eq. 8-1.3 in the book) reduces to:
dV/dt = R(dI/dt) + I/C
Homework Equations
The Attempt at a Solution
I've tried this about ten times and can't seem to get the right answer:
I found dV/dt = -37200 Sin(wt) (i'll call it v' from now on)
Rearranging the equation to make it in standard form:
dI/dt + (1/RC)I = v'/R
P= 1/RC = .0926
Q=v'/R = -62 Sin(wt)
F = ∫p dt
So e^F = e^.0926 t
and e^-F = e^-.0926 t
This equation was given in class for solving this type of DE:
I = (e^-I)∫Q*e^F dt + c1*e^-F
When plug this into mathematica, it gives me an imaginary answer
Any ideas?