Find the derivative of:y= (ax + sqrt of x^2 +b^2)^-2

  • Thread starter Thread starter ace123
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary
The discussion focuses on finding the derivative of the function y = (ax + √(x² + b²))⁻². One participant presents a derivative calculation resulting in -2(ax + √(x² + b²))⁻³ * (a + 2/√(x² + b²)) * 2x, while another agrees but notes a discrepancy regarding the term 2/√(x² + b²). There is also a mention of an alternative expression involving u, suggesting a different approach to the derivative. The conversation highlights confusion over the correct application of the chain and product rules in differentiation. Clarification on the derivative's accuracy is sought among participants.
ace123
Messages
250
Reaction score
0
The question is Find the derivative of:
y= (ax + sqrt of x^2 + b^2)^-2

I got this

-2(ax + sqrt of x^2 + b^2)^-3 *(a+ 2/ sqrt of x^2 + b^2) *2x

but i dno if this is right, can someone help me.
 
Physics news on Phys.org
Yea I got the same thing minus 2/ sqrt of x^2 + b^2

It should be 1/(2*biggiantmess^1/2)

or u^1/2 = 1/(2*u^1/2)
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K