Find the dimensions that will minimize the surface area of a Rectangle

In summary, to minimize the surface area of a rectangle, one must consider the relationship between its dimensions—length (L) and width (W). The surface area (A) is calculated as A = 2(LW + LH + WH), where H is the height if it’s a rectangular prism. To find the optimal dimensions, one typically applies calculus by taking the derivative of the surface area function, setting it to zero to find critical points, and analyzing these points to ensure they yield a minimum surface area. The optimal ratio of dimensions often approaches a square configuration when surface area minimization is the goal.
  • #1
chwala
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Homework Statement
See attached.
Relevant Equations
##\nabla f=0##
My interest is on number 11.

1701595731419.png


In my approach;

##v= xyz##

##1000=xyz##

##z= \dfrac{1000}{xy}##

Surface area: ##f(x,y)= 2( xy+yz+xz)##

##f(x,y)= 2\left( xy+\dfrac{1000}{x} + \dfrac{1000}{y}\right)##

##f_{x} = 2y -\dfrac{2000}{x^2} = 0##

##f_{y} = 2x -\dfrac{2000}{y^2} = 0##

On solving the simultaneous, i have

##2xy^2 - 2x^2y=0, 2xy(y-x)=0##

##(x_1, y_1) = (0,0)## is a critical point but ##x,y ≠ 0## leaving us with

##y-x=0, ⇒ y=x## thus,

##2x^3 - 2000=0##

##x_{2}=10, ⇒ y_{2} =10## and therefore ##z=\dfrac{1000}{100} =10##

thus the dimensions are ##(x,y,z) = (10,10,10)##.

also,

##D (10,10)= \left[\dfrac{4000}{x^3} ⋅ \dfrac{4000}{y^3} - 2^2 \right]= 16-4=12>0## and ##f_{xx} (10,10) = 4>0## implying that ##f## has a local minimum at ##(10,10).##

For avoidance of doubt, ##D = f_{xx} ⋅f_{yy} - (f_{yy})^2##

Your wise counsel is welcome or any insight. Cheers guys.
 
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  • #2
[tex]xyz=1000[/tex]
[tex]A=2(xy+yz+zx)=2000(\frac{1}{x}+\frac{1}{y}+\frac{1}{z})[/tex]
In symmetry we expect
[tex]\frac{1}{x}=\frac{1}{y}=\frac{1}{z}=\frac{1}{1000^{1/3}}=\frac{1}{10}[/tex]
is the case we seek. A=600. 

[EDIT]
We can prove that
[tex] \sqrt[3]{abc} \leq \frac{a+b+c}{3} [/tex]
 
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FAQ: Find the dimensions that will minimize the surface area of a Rectangle

What is the formula for the surface area of a rectangle?

The surface area of a rectangle is calculated using the formula: Surface Area = 2(lw + lh + wh), where l is the length, w is the width, and h is the height of the rectangle.

How do you determine the dimensions that minimize the surface area of a rectangle?

To determine the dimensions that minimize the surface area, you can use calculus. Specifically, you would set up the surface area formula as a function of one variable, take its derivative, set the derivative equal to zero, and solve for the variable. This will give you the dimensions that minimize the surface area.

Is there a specific method or approach to solve this optimization problem?

Yes, the method typically involves using the method of Lagrange multipliers or setting up a constraint equation (such as a fixed volume) and then using calculus to find the critical points that minimize the surface area.

Can the dimensions that minimize the surface area be found using algebra alone?

While algebra can help set up the problem and simplify the equations, calculus is generally required to find the precise dimensions that minimize the surface area because it involves finding and analyzing critical points.

What are the real-world applications of minimizing the surface area of a rectangle?

Minimizing the surface area of a rectangle has several real-world applications, including packaging design to reduce material costs, optimizing shapes for thermal efficiency in engineering, and designing containers to maximize storage while minimizing surface exposure.

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